我试图从我的数据库中返回最后10条记录,并将它们显示在网页上。下面的代码只返回一条记录,有人知道我哪里出错了吗?我稍后会用一张桌子整理它,暂时我只需要最后10张唱片。
该表的名称为“devel”,列名为: id、STATION、REASON_CODE、ERROR、WEEK、注释、停机时间、日期。
$dbc = mysqli_connect(‘xxxx’, ‘xxxx’, 'xxxx', ‘xxxx’)
or die('Error connecting to MySQL server.');
$query = "SELECT * FROM devel ORDER BY id DESC LIMIT 10";
$result = mysqli_query($dbc, $query)
or die('Error querying database.');
while($record = mysqli_fetch_array($result)){
echo $record['id']. " " .$record['STATION'] . " " . $record['REASON_CODE'] . " " . $record['ERROR']. " " .$record['WEEK'] . " " .$record['COMMENT'] . " " .$record['DOWNTIME'] . " " .$record['DATE'];
echo "<br /";
}发布于 2015-11-03 18:53:57
试试这个
$dbc = mysqli_connect(‘xxxx’, ‘xxxx’, 'xxxx', ‘xxxx’)
or die('Error connecting to MySQL server.');
$query = "SELECT * FROM devel ORDER BY id DESC LIMIT 10";
$result = mysqli_query($dbc, $query)
or die('Error querying database.');
echo "<table><tr>
<th>Id</th>
<th>STATION</th>
<th>REASON_CODE</th>
<th>ERROR</th>
<th>WEEK</th>
<th>COMMENT</th>
<th>DOWNTIME</th>
<th>DATE</th>
</tr>";
while($record = mysqli_fetch_assoc($result)){
echo "<tr>";
echo "<td>".$record['id']."</td>";
echo "<td>".$record['STATION']."</td>";
echo "<td>".$record['REASON_CODE']."</td>";
echo "<td>".$record['ERROR']."</td>";
echo "<td>".$record['WEEK']."</td>";
echo "<td> ".$record['COMMENT']."</td>";
echo "<td> ".$record['DOWNTIME']."</td>";
echo "<td> ".$record['DATE']."</td>";
echo "</tr>";
}
echo "</table>";https://stackoverflow.com/questions/33506504
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