宣布胜利者代码

Question

我想知道是否有人能帮我这个忙。这是一个简单的橄榄球冠军播音员。代码有时运行得很好，而其他时候却不太好。

team1 = input ("Team 1: ")
score1 = input("Score: ")
team2 = input("Team 2: ")
score2 = input("Score: ")

if score1 >= score2:
  print (team1 + " beat " + team2 + " " + score1 + "-" + score2)
else:
  print(team2 + " beat " + team1 + " " + score2 + "-" + score1)

这是一个正在工作的例子：

Team 1: england
Score: 35
Team 2: fiji
Score: 11
england beat fiji 35-11

但是，当我输入它时，它不起作用：

Team 1: Wales
Score: 54
Team 2: Urguary
Score: 9
Urguary beat Wales 9-54

有人能看出是怎么回事吗？任何帮助都很感激。

Answer 1

您的比较没有按预期的方式工作，因为它是比较字符串，而不是数字。字符串按字典顺序进行比较，因此9比54高，就像Z按字母顺序排列在AA之后一样。

要使代码工作，请将用户获得的分数转换为使用int的整数。

team1 = input ("Team 1: ")
score1 = int(input("Score: "))
team2 = input("Team 2: ")
score2 = int(input("Score: "))

Answer 2

team1 = input ("Team 1: ")
score1 = input("Score: ")
team2 = input("Team 2: ")
score2 = input("Score: ")

if int(score1) >= int(score2):
  print (team1 + " beat " + team2 + " " + score1 + "-" + score2)
else:
  print(team2 + " beat " + team1 + " " + score2 + "-" + score1)

Answer 3

我建议比较值，输入值时使用整数或浮点数，或者在比较之前使其为整数或浮点数。

要么立即做

score1 = int(input("Score: ")

或紧接其后

score1 = input("Score: ") score1 = int(score1)

或者就像比较

if int(score1) >= int(score2):