HtmlUnit谷歌登录

Question

我想自动化google登录并接受oauth以获得身份验证代码。

我通过NullPointerExeption ()得到一个nextButton.click()，找不到"next“按钮。

        WebClient webClient = new WebClient(); //BrowserVersion.FIREFOX_38
        HtmlPage page = webClient.getPage("https://accounts.google.com/o/oauth2/auth?");            

        HtmlTextInput email = (HtmlTextInput)page.getElementById("Email");
        email.setValueAttribute(emailAddress);
        HtmlSubmitInput nextButton = (HtmlSubmitInput)page.getElementById("next");

        HtmlPage newPage = (HtmlPage)nextButton.click();
        webClient.waitForBackgroundJavaScriptStartingBefore(8000);

        HtmlTextInput passwd = (HtmlTextInput)page.getElementById("Passwd");
        passwd.setValueAttribute(password);
        HtmlSubmitInput signIn = (HtmlSubmitInput)page.getElementById("signIn");

        HtmlPage pageSucces = (HtmlPage)signIn.click();
        webClient.waitForBackgroundJavaScriptStartingBefore(8000);

        HtmlSubmitInput submitAccess = (HtmlSubmitInput)page.getElementById("submit_approve_access");
        HtmlPage pageAccess = (HtmlPage)submitAccess.click();
        webClient.waitForBackgroundJavaScriptStartingBefore(8000);

        HtmlTextInput code = (HtmlTextInput)page.getElementById("code");
        System.out.println(code.getText());

我试过这个Can't log in to Google using HtmlUnit - Can't advance to web page for entering password，但没有成功。

Answer 1

问题是网站，html页面不像标准浏览器。登录页面如下所示：https://lh6.ggpht.com/v19i1LtG-IdZKSZ-rhtuflJJmVmZM3gd3uauQQyLFvJxXTxYi4t8ygCQXwutu1nq69mmna8=w351

您还可以查看页面对象，在那里可以看到带有所有可用ID的idMap。

        HtmlTextInput email = (HtmlTextInput)page.getElementById("Email");
        email.setValueAttribute(emailAddress);
        HtmlPasswordInput passwd = (HtmlPasswordInput)page.getElementById("Passwd");
        passwd.setValueAttribute(password);
        HtmlSubmitInput signInButton = (HtmlSubmitInput)page.getElementById("signIn");

        webClient.waitForBackgroundJavaScriptStartingBefore(8000);
        HtmlPage newPage = (HtmlPage)signInButton.click();