我需要用密码和密码确认来验证简单的JavaFX表单。
validationSupport.registerValidator(passwordInput,
Validator.createEmptyValidator("Password required!"));
validationSupport.registerValidator(confirmPasswordInput,
new EqualsToValidator(passwordInput.textProperty(),
"Password differs from confirmation"));在EqualsToValidator中,我简单地比较了传递给验证器的property.getValue()和value。
如果我只更改密码,则不会调用EqualsToValidator,因为它正在侦听confirmPasswordInput而不是passwordInput。
我只找到了丑陋的解决办法:
passwordInput.textProperty().addListener((observable, oldValue, newValue) -> {
String oldText = confirmPasswordInput.getText();
confirmPasswordInput.setText(null);
confirmPasswordInput.setText(oldText);
});如何使一个字段在另一个字段更改时失效?
发布于 2015-11-04 04:46:54
Validator.java -验证器的基类。
TextValidator.java和PasswordValidator.java -实现。
ValidationSupport.java跟踪所有验证器。
用法:
validationSupport.addValidator(new TextValidator(usernameInput, "Username is required!"));
validationSupport.addValidator(new TextValidator(passwordInput, "Password is required!"));
validationSupport.addValidator(new PasswordValidator(passwordInput, confirmPasswordInput, "Password differs from confirmation"));发布于 2017-03-28 15:55:25
这对我有用。我只是复制了ValidationSupport类并添加了折叠代码。
@SuppressWarnings("unchecked")
public <T> void reaplyValidator(Control target){
if(!controls.containsKey(target)){
throw new NullPointerException("The given control was not registered");
}
ValueExtractor.getObservableValueExtractor(target).map( e -> {
ObservableValue<T> observable = (ObservableValue<T>) e.call(target);
Validator<T> validator = (Validator<T>) controls.get(target);
Platform.runLater(() -> validationResults.put(target, validator.apply(target, observable.getValue())));
dataChanged.set(true);
return e;
});
}
public void revalidate(){
for(Control c : getRegisteredControls()){
reaplyValidator(c);
}
}您还需要将控件设置为Map,以便保持验证器。
private ObservableMap<Control, Validator<?>> controls = FXCollections.observableMap(new HashMap<>());https://stackoverflow.com/questions/33393159
复制相似问题