我是新来的,当我使用turn.js显示页面翻转时,我的脚本出现了问题。我的页面来自mysql数据库,以json格式存储,然后解析到JavaScript中的数组,通过turn.js查看。
这是我的密码:
<body>
<?php
$json_array = Array();
include("setdb.php");
$query="select * from catalogue_page where catalogue_id='5'";
$result=mysql_query($query);
$totalrec=mysql_num_rows($result);
while ($hasil=mysql_fetch_array($result)){
$data= "images/pages/small/".$hasil['img_file_small'];
array_push($json_array, $data);
}
$json_array2 = array();
$query="select * from catalogue_page where catalogue_id='5'";
$result=mysql_query($query);
while ($hasil=mysql_fetch_array($result)){
$data="images/pages/large/".$hasil['img_file_large'];
array_push($json_array2, $data);
}
?>
<div class="magazine-viewport">
<div class="container">
<div class="magazine">
</div>
</div>
</div>
<script type="text/javascript">
var page_image = Array();
var page_image_large = new Array();
page_image = JSON.parse( '<?php echo json_encode($json_array)?>' );
page_image_large = JSON.parse( '<?php echojson_encode($json_array2)?>'
);
......
......
next script from turn.js
</script>该脚本显示从1色开始的页面,而不是从0列开始。
浏览器中的从turn.js /turn.js/small/2_5.jpg开始显示页面,而不是显示图像/页面/small/1_5.jpg
我的json解析是
( '["images\/pages\/small\/1_5.jpg","images\/pages\/small\/2_5.jpg","images\/pages\/small\/3_5.jpg","images\/pages\/small\/4_5.jpg","images\/pages\/small\/5_5.jpg","images\/pages\/small\/6_5.jpg"]' ); 0色为images\/pages\/small\/1_5.jpg
1色为images\/pages\/small\/2_5.jpg .下一色
发布于 2015-10-25 12:23:53
最后,我是正确的,我的脚本和转机显示页面的魅力,在这里,我的正确的脚本:
<script type="text/javascript">
var page_image = new Array();
var page_image_large = new Array();
var tampung1 = JSON.parse( '<?php echo json_encode($json_array)?>');
var tampung2 = JSON.parse( '<?php echo json_encode($json_array2)?>');
var j=1;
for(i=0;i<<?php echo $totalrec?>;i++)
{
page_image[j] = tampung1[i];
page_image_large[j] = tampung2[i];
j++
}
.....
next turnjs script
</script>不管怎样,谢谢你的关注。
https://stackoverflow.com/questions/33297062
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