Symfony Formbuilder获取pathInfo

Question

是否有一种方法可以在pathInfo函数中返回页面的buildForm或URL？

class RoomType extends AbstractType
{
    /**
     * {@inheritdoc}
     */
     public function buildForm(FormBuilderInterface $builder, array $options)
{

 VarDumper::dump($builder->getRequestHandler());

Answer 1

只有在有请求对象的情况下。一个选项是在构造表单时传递请求。

你的控制器动作

$form = $this->createForm(new RoomType($request), new Room());

您的表单类型类

class RoomType extends AbstractType
{
    protected $request;

    public function __construct(Request $request) {
        $this->request = $request;
    }

    /**
     * {@inheritdoc}
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        VarDumper::dump($this->request);
    }
}