当我在JDeveloper中运行下面的java代码时,我得到了错误的输出。原因是什么呢?
System.out.println(TimeZone.getTimeZone("Australia/Sydney").inDaylightTime(new Date()));
System.out.println(TimeZone.getTimeZone("Europe/Moscow").inDaylightTime(new Date()));我期望输出为:真假
但是,我明白它是假的。
PS:这对于“美国/韦恩堡”和“欧洲/柏林”这样的时区来说是正确的。
发布于 2015-10-14 10:24:52
由于new Date()的使用并不完全遵循How to create a Minimal, Complete, and Verifiable example的原则,因此如下所示:
public static void main(String[] args) {
Date date = new Date(1444817534489L); // 2015-10-14 10:12:14.489 UTC
printDate(date, "UTC");
printDate(date, "Australia/Sydney");
printDate(date, "Europe/Moscow");
printDate(date, "Europe/Berlin");
printDate(date, "America/Fort_Wayne");
}
private static void printDate(Date date, String timeZoneID) {
TimeZone timeZone = TimeZone.getTimeZone(timeZoneID);
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS z");
df.setTimeZone(timeZone);
System.out.printf("%-20s %-30s inDaylightTime: %s%n", timeZoneID + ":",
df.format(date), timeZone.inDaylightTime(date));
}输出
UTC: 2015-10-14 10:12:14.489 UTC inDaylightTime: false
Australia/Sydney: 2015-10-14 21:12:14.489 AEDT inDaylightTime: true
Europe/Moscow: 2015-10-14 13:12:14.489 MSK inDaylightTime: false
Europe/Berlin: 2015-10-14 12:12:14.489 CEST inDaylightTime: true
America/Fort_Wayne: 2015-10-14 06:12:14.489 EDT inDaylightTime: true所以,true false正如你所期望的。如果你看到不同的,也许你的约会是不同的,如果没有打印,你怎么会知道?
https://stackoverflow.com/questions/33122438
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