我想使用这种方法,但是我连简单的例子都找不到。我可能误解了这个概念,但据我所知,它允许交换方法实现。
给定两个方法,A和B,我想交换它们的实现,这样调用A就会执行B。我看到了一些swizzling的例子(example1和example2)。我创建了一个带有类的新项目来测试这个项目。
class Swizzle: NSObject
{
func method()
{
print("A");
}
}
extension Swizzle
{
override class func initialize()
{
struct Static
{
static var token: dispatch_once_t = 0;
}
// make sure this isn't a subclass
if (self !== Swizzle.self)
{
return;
}
dispatch_once(&Static.token)
{
let originalSelector = Selector("method");
let swizzledSelector = Selector("methodExt");
let originalMethod = class_getInstanceMethod(self, originalSelector);
let swizzledMethod = class_getInstanceMethod(self, swizzledSelector);
print(method_getImplementation(originalMethod));
print(method_getImplementation(swizzledMethod));
let didAddMethod = class_addMethod(self, originalSelector, method_getImplementation(swizzledMethod), method_getTypeEncoding(swizzledMethod));
if didAddMethod
{
class_replaceMethod(self, swizzledSelector, method_getImplementation(originalMethod), method_getTypeEncoding(originalMethod));
}
else
{
method_exchangeImplementations(originalMethod, swizzledMethod);
}
print(method_getImplementation(originalMethod));
print(method_getImplementation(swizzledMethod));
}
}
func methodExt()
{
print("B");
}
}然后我试着用
var s = Swizzle();
s.method();预期输出为"B",但仍在打印"A“。从我的代码中可以看到,我在执行swizzle操作之前和之后都包含了每个IMP的打印。这些打印显示,交换确实发生了,但输出保持不变。
输出:
0x000000010251a920
0x000000010251ad40
0x000000010251ad40
0x000000010251a920
A在让这些改变生效的时候,我有什么遗漏吗?
PS。目前使用XCode 7.0.1
发布于 2015-10-13 08:23:18
问题是您的method()缺少dynamic指令:
class Swizzle: NSObject
{
dynamic func method()
{
print("A")
}
}修改声明,它应该能工作。
在Swift中使用方法swizzling时,类/方法必须遵守两个要求:
NSObjectdynamic属性。有关为什么需要这样做的完整解释,请参阅使用Swift与Cocoa和Objective
需要动态调度 虽然
@objc属性将Swift公开给Objective运行时,但它并不保证动态分配属性、方法、下标或初始化器。Swift编译器仍然可以取消虚拟化或内联成员访问,以优化代码的性能,从而绕过Objective运行时。使用dynamic修饰符标记成员声明时,总是动态地分配对该成员的访问。因为使用dynamic修饰符标记的声明是使用Objective运行时分派的,所以它们被隐式标记为@objc属性。 很少需要动态调度。但是,当您知道在运行时dynamic的实现被替换时,必须使用修饰符。例如,您可以在Objective运行时使用method_exchangeImplementations函数来在应用程序运行时交换方法的实现。如果Swift编译器将方法的实现内联或对其进行去虚拟化访问,则不会使用新的实现。
Swift 3更新:
在GCD方面已经有了一些变化,dispatch_once不再可用了。要执行相同的一次操作,我们可以将代码封装在全局静态类常量的初始化块中。
Swift语言保证此代码在应用程序生命周期内只执行一次。
class TestSwizzling : NSObject {
dynamic func methodOne()->Int{
return 1
}
}
extension TestSwizzling {
//In Objective-C you'd perform the swizzling in load(),
//but this method is not permitted in Swift
override class func initialize()
{
struct Inner {
static let i: () = {
let originalSelector = #selector(TestSwizzling.methodOne)
let swizzledSelector = #selector(TestSwizzling.methodTwo)
let originalMethod = class_getInstanceMethod(TestSwizzling.self, originalSelector);
let swizzledMethod = class_getInstanceMethod(TestSwizzling.self, swizzledSelector)
method_exchangeImplementations(originalMethod, swizzledMethod)
}
}
let _ = Inner.i
}
func methodTwo()->Int{
// It will not be a recursive call anymore after the swizzling
return methodTwo()+1
}
}
var c = TestSwizzling()
print(c.methodOne())
print(c.methodTwo())SWIFT2.2更新:
我更新了新#selector属性的原始示例:
class TestSwizzling : NSObject {
dynamic func methodOne()->Int{
return 1
}
}
extension TestSwizzling {
//In Objective-C you'd perform the swizzling in load(),
//but this method is not permitted in Swift
override class func initialize()
{
struct Static
{
static var token: dispatch_once_t = 0
}
// Perform this one time only
dispatch_once(&Static.token)
{
let originalSelector = #selector(TestSwizzling.methodOne)
let swizzledSelector = #selector(TestSwizzling.methodTwo)
let originalMethod = class_getInstanceMethod(self, originalSelector);
let swizzledMethod = class_getInstanceMethod(self, swizzledSelector)
method_exchangeImplementations(originalMethod, swizzledMethod)
}
}
func methodTwo()->Int{
// It will not be a recursive call anymore after the swizzling
return methodTwo()+1
}
}
var c = TestSwizzling()
print(c.methodOne())
print(c.methodTwo())如果您需要使用一个示例,请查看此示例项目论github。
https://stackoverflow.com/questions/33096873
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