用CryptoSwift和Ruby填充错误

Question

我很难让CryptoSwift和Ruby's OpenSSL AES玩得很好

我的Swift代码：

let key = ("12345678901234567890123456789012" as NSString).dataUsingEncoding(NSUTF8StringEncoding)?.arrayOfBytes() //32 chars because im testing AES 256
let iv = Cipher.randomIV(AES.blockSize)
let data = NSData(bytes: iv, length: Int(iv.count))
let ivstring = data.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0));
print(ivstring)

let message = "Hello World".dataUsingEncoding(NSUTF8StringEncoding)?.arrayOfBytes()

    do
    {

        let encrypted = try AES(key: key!, iv: iv, blockMode: .CBC)?.encrypt(message!, padding: PKCS7())
        let decrypted = try AES(key: key!, iv: iv, blockMode: .CBC)?.decrypt(encrypted!, padding: PKCS7())

        let encData = NSData(bytes: encrypted!, length: Int(encrypted!.count))
        let base64String: String = encData.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0));
        let result = String(base64String)
        print(result)

        let decData = NSData(bytes: decrypted!, length: Int(decrypted!.count))
        let result2 = NSString(data: decData, encoding: NSUTF8StringEncoding)
        print(result2!)

    }
    catch
    {

    }

其中产出：

7oR9lu+ROC7PW7bDqXcRxw==
XzZj2OTTbA8zaedeoVh0KA==
Hello World

然后，在Ruby中，我需要：

key = "12345678901234567890123456789012"
iv = "7oR9lu+ROC7PW7bDqXcRxw=="

encrypted = "XzZj2OTTbA8zaedeoVh0KA=="

decipher = OpenSSL::Cipher::AES.new(256, :CBC)
decipher.decrypt
decipher.key = key
decipher.iv = iv
plain = decipher.update(encrypted) + decipher.final

红宝石代码在最后一行plain = decipher.update(encrypted) + decipher.final上抛出一个错误，声明：

OpenSSL::Cipher::CipherError
=================================================
> wrong final block length

我显然不是最有经验的加密人员，但你能给我的任何帮助都会非常感谢！

Answer 1

在解密之前，您需要对数据和iv进行64位解码。您目前正在通过AES直接发送64基编码数据。

解密后别忘了剥去垫子。