DayOfWeek获得下一个DayOfWeek(星期一，Tuesday...Sunday)

Question

有没有办法将这段代码概括成1-2行？

我的目标是返回，例如，我有一个DayOfWeek，这是星期一，我想得到的第二天(星期二)或n天之后。

         switch (_RESETDAY)
        {
            case DayOfWeek.Monday:
                _STARTDAY = DayOfWeek.Tuesday;
                break;
            case DayOfWeek.Tuesday:
                _STARTDAY = DayOfWeek.Wednesday;
                break;
            case DayOfWeek.Wednesday:
                _STARTDAY = DayOfWeek.Thursday;
                break;
            case DayOfWeek.Thursday:
                _STARTDAY = DayOfWeek.Friday;
                break;
            case DayOfWeek.Friday:
                _STARTDAY = DayOfWeek.Saturday;
                break;
            case DayOfWeek.Saturday:
                _STARTDAY = DayOfWeek.Sunday;
                break;
            case DayOfWeek.Sunday:
                _STARTDAY = DayOfWeek.Monday;
                break;
            default:
                _STARTDAY = DayOfWeek.Tuesday;
                break;
        }

Answer 1

这只是一个int枚举，范围从星期日(0)到星期六(6)，如MSDN所示：

DayOfWeek枚举以每周有七天的日历表示一周中的一天。此枚举中常量的值从DayOfWeek.Sunday到DayOfWeek.Saturday不等。如果转换为整数，则其值从零(指示DayOfWeek.Sunday)到六(指示DayOfWeek.Saturday)。

所以简单的数学应该做到：

DayOfWeek nextDay = (DayOfWeek)(((int)_RESETDAY + 1) % 7);

如果需要的话，用+ 1替换为+ n。

Answer 2

是。

(DayOfWeek)((int)(_RESETDAY+1)%7)

Answer 3

与上面回答的添加和模块的结果相同，但是更易读的imho：

day = (day == DayOfWeek.Saturday) ? DayOfWeek.Sunday : day + 1;

显而易见的代码意图总是更令人愉快。