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Postgres JSON输出
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Stack Overflow用户
提问于 2015-09-23 15:13:52
回答 1查看 136关注 0票数 0

我有一个查询输出:-

代码语言:javascript
复制
indicator1,company1,value1
indicator1,company2,value2
indicator1,company3,value3
indicator2,company1,value4
indicator2,company2,value5
indicator2,company3,value6
....

如何将此输出转换为以下json结构:

代码语言:javascript
复制
{
 indicator1 :{
              "companies" : ["company1","company2","company3"],
              "values"    : ["value1","value2","value3"]
             },
 indicator2 :{
              "companies" : ["company1","company2","company3"],
              "values"    : ["value4","value5","value6"]
             }
}...

我在用postgres 9.4

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回答 1

Stack Overflow用户

回答已采纳

发布于 2015-09-23 15:48:26

使用json_build_object()json_agg()

代码语言:javascript
复制
with q1 as (
    select * from 
        (values 
            ('indicator1', 'company1', 'value1'),
            ('indicator1', 'company2', 'value2'),
            ('indicator1', 'company3', 'value3'),
            ('indicator2', 'company1', 'value4'),
            ('indicator2', 'company2', 'value5'),
            ('indicator2', 'company3', 'value6')
        ) alias(ind, comp, val)
    ),
q2 as (
    select ind, to_json(array_agg(comp)) companies, to_json(array_agg(val)) "values"
    from q1
    group by 1
    order by 1
    ),
q3 as (
    select companies, "values"
    from q2
    ),
q4 as (
    select json_build_object(ind, row_to_json (q3)) obj
    from q2
    join q3 on q2.companies::text = q3.companies::text and q2."values"::text = q3."values"::text
    )
select json_agg(obj)
from q4;

替代压缩解决方案,它避免了笨拙的连接条件:

代码语言:javascript
复制
with q1 as (
    select * from 
        (values 
            ('indicator1', 'company1', 'value1'),
            ('indicator1', 'company2', 'value2'),
            ('indicator1', 'company3', 'value3'),
            ('indicator2', 'company1', 'value4'),
            ('indicator2', 'company2', 'value5'),
            ('indicator2', 'company3', 'value6')
        ) alias(ind, comp, val)
    ),
q2 as (
    select ind, to_json(array_agg(comp)) companies, to_json(array_agg(val)) "values"
    from q1
    group by 1
    order by 1
    )
select json_agg(
    json_build_object(
        ind, 
        json_build_object(
            'companies', companies, 
            'values', "values")
        )
    )
from q2
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/32743353

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