我试图使用ruby代码查询Artifactory的AQL,我已经检查了这个代码是否可以使用curl在bash上工作:
curl -u admin:password -i -H "Accept: application/json" -X POST http://server.example.com:8081/artifactory/api/search/aql -T aql.aql
其中aql.aql内容如下:
items.find
(
{
"repo":{"$eq":"test-ASO"}
}
)
.include("name","property.*")现在,我尝试使用Ruby对以下代码进行同样的操作:
#!/usr/bin/ruby
require 'rubygems'
require 'json'
require 'open-uri'
require 'uri'
require 'net/http'
payload ='items.find
(
{
"repo":{"$eq":"test-ASO"}
}
).include("name","property.*")'
uri = URI.parse("http://server.example.com:8081/artifactory/api/search/aql")
http = Net::HTTP.new(uri.host,uri.port)
req = Net::HTTP::Post.new(uri.path)
req.basic_auth 'user', 'password'
req.set_form_data(payload)
res = http.request(req)
puts res.body但我得到的只是:
{
"errors" : [ {
"status" : 400,
"message" : "Bad Request"
} ]
}我的猜测是,查询的有效负载必须是一个文件,正如我以前对curl (-T参数)所做的那样,但我不认为使用文件进行查询是实现这一目标的一种非常优雅的方法。
发布于 2015-09-22 12:39:28
编辑
最后,我通过声明具有适当内容的req.body变量实现了这一点:
#!/usr/bin/ruby
require 'rubygems'
require 'json'
require 'open-uri'
require 'uri'
require 'net/http'
payload = 'items.find().include("name","property.*")'
uri = URI.parse("http://server.example.com:8081/artifactory/api/search/aql")
http = Net::HTTP.new(uri.host,uri.port)
req = Net::HTTP::Post.new(uri.path)
req["Content-Type"] = "text/plain"
req.basic_auth 'admin', 'password'
req.body = payload
res = http.request(req)
puts res.bodyhttps://stackoverflow.com/questions/32711816
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