为短语创建WPM计数器，然后输出所需时间

Question

因此，我想使用time.monotonic()函数创建一个简单的程序，在用户输入该短语之前和之后提示它，然后每分钟给出avg单词以及输入该短语所需的总秒数。

短语：“敏捷的棕色狐狸跳过懒惰的狗。”

我是编程新手，所以我会给出我下面的代码和粗略的想法，请随时纠正我。所有的帮助都是感激的。

import time 

inputText = str(input('Enter the phrase :"The quick brown fox jumps over the lazy dog" as fast as possible')

t0 = time.time() #start time
t1 = time.time() #stop time

timeTaken = t1 - t0
wordPM = (9/timeTaken)

#print time taken in seconds and avg WPM

好的，我接受了第一张海报的建议，但是当我在输入“是”继续后运行代码时，它会停止，没有错误，所以我不能确定是什么问题。

import time 
string = "The quick brown fox jumps over the lazy dog"
word_count = len(string.split())

while str(input('Enter "yes" when you are ready')) != 'yes':
str(input('Enter "yes" when you are ready'))
t0 = time.time() #start time
inputText = str(input('Enter the phrase :"The quick brown fox jumps over the lazy dog" as fast as possible' % string))
t1 = time.time() #stop time  
acc = len(set(inputText.split()) & set(string.split()))
acc = acc/word_count
timeTaken = t1 - t0
wordPM = (word_count/timeTaken)
print (wordPM, acc)  

Answer 1

import time 
string = "The quick brown fox jumps over the lazy dog"
word_count = len(string.split())

您可以用一些介绍来为用户做准备。

while str(raw_input('Enter "yes" when you are ready')) <> 'yes':
    str(raw_input('Enter "yes" when you are ready'))

然后启动你的计时器

t0 = time.time() #start time
inputText = str(raw_input('Enter the phrase :"%s" as fast as possible' % string))
t1 = time.time() #stop time

然后以某种方式计算正确输入单词的百分比。

acc = len(set(inputText.split()) & set(string.split()))
acc = acc/word_count

timeTaken = t1 - t0
wordPM = (word_count/timeTaken)
print wordPM, acc