通过在php中查找json对象的值来计数json对象

Question

我有这个json数据。如何使用leader来计数对象我想要计数"leader": "true"

这是我的json:在本例中，"leader":"true"的计数是1

[
{
"id":23,
"uid":"0090000219",
"cid":"0090000013",
"extension":"201",
"secret":"Myojyo42_f",
"leader":true,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-02 12:49:12",
"updated_at":"2015-09-02 12:49:12"
},
{
"id":24,
"uid":"0090000221",
"cid":"0090000013",
"extension":"203",
"secret":"Myojyo42_f",
"leader":false,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-02 12:49:12",
"updated_at":"2015-09-02 12:49:12"
},
{
"id":25,
"uid":"0090000223",
"cid":"0090000013",
"extension":"205",
"secret":"Myojyo42_f",
"leader":false,
"simultaneous":false,
"confbridge_id":17,
"created_at":"2015-09-10 10:16:24",
"updated_at":"2015-09-10 10:16:24"
}
]

这是我的密码：

        foreach($apiResults['conference_participants'] as &$record) {
           $leader_count = count(record['leader']);  
        }

Answer 1

首先解码它，然后返回，然后计数数据leader。

试试这个：

$decoded = json_decode($json, true);



     $count = 0;
    foreach($decoded as $key => $val)
    {
       if($val['leader'] == 1)
       {
           $count++;
       }
    }
    echo $count;
       //if you want also to count the false then add else in the statement echo  $count++;
    }

Answer 2

这会成功的..。测试和确认

$data = json_decode($json, true);
$count=0;
    foreach($data as $key => $val)
    {
       if($val['leader'] == 1)
       {
           $count++;
       }
    }
    echo $count;

Answer 3

这可以通过使用count函数以及array_filter和json_decode来完成。

echo count (array_filter(json_decode($json), 
                         function($a){ return $a->leader?1:0;}));

从内到外：

首先，json_decode将字符串生成一个stdClass对象数组。

然后，array_filter使用回调筛选出领导者属性为false的条目。

最后，计数可以让您知道返回数组中有多少个元素。