无法解析Sendgrid将api原始回调解析为Griddler电子邮件对象

Question

我正在努力做到以下几点：

把所有的电子邮件发送到我的领域，分析他们的内容，身体，主题行和.以便我从它构造一个传真对象，并将它作为传真发送。

到目前为止，我已经能够设置我的MX记录指向Sendgrid，并使用Ngrok从Sendgrid的Parse中获得本地主机服务器中的回调。下一步是将原始对象转换为我可以使用的对象。这让我找到了Thoughbot的Griddler宝石。

到目前为止，我是如何安装我的应用程序的：

Sendgrid安装程序: URL：处理器收垃圾邮件检查和发送原始文件都被选中

正如前面提到的，由于我确实收到了这篇文章，所以这部分起作用了：

Parameters: {"dkim"=>"{@gmail.com : pass}", "email"=>"Received: by mx0034p1mdw1.sendgrid.net with SMTP id 253FfvZ40f Wed, 09 Sep 2015 22:31:48 +0000 (UTC)\nReceived: from mail-qg0-f54.google.com (mail-qg0-f54.google.com [209.85.192.54]) by mx0034p1mdw1.sendgrid.net (Postfix) with ESMTPS id 63848A83017 for <14085552422@faxbyemail.co>; Wed,  9 Sep 2015 22:31:48 +0000 (UTC)\nReceived: by qgx61 with SMTP id 61so21251135qgx.3 for <14085552422@faxbyemail.co>; Wed, 09 Sep 2015 15:31:48 -0700 (PDT)\nDKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:from:date:message-id:subject:to:content-type; bh=Wo6p7CSlR30aGxf5SwjuZ2klt31URDqTZUHrKdmLz7s=; b=fWfFOQ4YOtijYvphYL9/1shyzK8CBTcHS37s89t9Qn4xK8OrXwVKtmGtNnwg7a1n48 JHkEeAdxVvRMpinxPllGiJoPNy0ivVN36uEYbsrLTcZVlx9RIIl8u5PjmrE1aqlnkjPy gOcbfJunVCFZLaLpv3RB/GiNYL1bodgW7nn8sMTmwN5EwoH7SncS7cle4ksPadgiGv9f DVoJniX2yuMqygSVLT4Qrk4JDzR6G2oj1Fz3QkcrQfNKxOS6iyBhpnh3cDuUi8GTSVYl Nqq2dtKlUNqI+U9ojtG1BjGVUKbP0v5apF3Wvmj72p8L0AB3FHqL8uvFnhi2dGTFVq+y 6nUQ==\nX-Received: by 10.140.233.137 with SMTP id e131mr48879201qhc.37.1441837907953; Wed, 09 Sep 2015 15:31:47 -0700 (PDT)\nMIME-Version: 1.0\nFrom: Sam Sedighian <samansb@gmail.com>\nDate: Wed, 09 Sep 2015 22:31:38 +0000\nMessage-ID: <CAEMkzYbhsLLB3NPLznG+-RibP5kzDG5yTT++mQL1ep-vH6_orA@mail.gmail.com>\nSubject: test 20\nTo: \"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>\nContent-Type: multipart/alternative; boundary=001a11354d8053d2d1051f580c22\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/plain; charset=UTF-8\n\nbody etxt\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/html; charset=UTF-8\n\n<div dir=\"ltr\">body etxt</div>\n\n--001a11354d8053d2d1051f580c22--\n", "to"=>"\"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>", "from"=>"Sam Sedighian <samansb@gmail.com>", "sender_ip"=>"209.85.192.54", "spam_report"=>"Spam detection software, running on the system \"mx0034p1mdw1.sendgrid.net\", has\nidentified this incoming email as possible spam.  The original message\nhas been attached to this so you can view it (if it isn't spam) or label\nsimilar future email.  If you have any questions, see\n@@CONTACT_ADDRESS@@ for details.\n\nContent preview:  body etxt body etxt [...] \n\nContent analysis details:   (0.0 points, 5.0 required)\n\n pts rule name              description\n---- ---------------------- --------------------------------------------------\n 0.0 FREEMAIL_FROM          Sender email is freemail (samansb[at]gmail.com)\n 0.0 HTML_MESSAGE           BODY: HTML included in message\n 0.0 T_MIME_NO_TEXT         No text body parts\n\n", "envelope"=>"{\"to\":[\"14085552422@faxbyemail.co\"],\"from\":\"samansb@gmail.com\"}", "subject"=>"test 20", "spam_score"=>"0.012", "charsets"=>"{\"to\":\"UTF-8\",\"subject\":\"UTF-8\",\"from\":\"UTF-8\"}", "SPF"=>"pass"}

Gemfile

gem 'griddler'
gem 'griddler-sendgrid'

Gemfile.lock

griddler (1.2.1)
  htmlentities
  rails (>= 3.2.0)
griddler-sendgrid (0.0.1)
  griddler

routes.rb

post '/email_processor' => 'fax#sendgrid'
# this corresponds to the following route when I rake route:
# email_processor POST   /email_processor(.:format) fax#sendgrid

config/initializers/griddler.rb

Griddler.configure do |config|
  config.processor_class = EmailProcessor
  config.processor_method = :process
  config.reply_delimiter = '-- REPLY ABOVE THIS LINE --'
  config.email_service = :sendgrid
end

app/controllers/fax_controller.rb

def sendgrid
  EmailProcessor.new(params).process
end

app/models/email_processor.rb

class EmailProcessor

  def initialize(email)
    @email = email
    @from = email.from
    @body = email.body
  end

  def self.process(email)
    Fax.create({params go here})
  end

end

最后，我给出了一个完整的500内部服务器错误--因为我没有将200 OK传回Sendgrid，但重要的是我在日志中得到了以下错误：

NoMethodError (undefined method `from' for #<ActionController::Parameters:0x007fc742a33070>):
  app/models/email_processor.rb:5:in `initialize'
  app/controllers/fax_controller.rb:31:in `new'
  app/controllers/fax_controller.rb:31:in `sendgrid'

Answer 1

我认为问题在于，您正在绕过Griddler在控制器端所做的工作。您将Sendgrid指向您自己创建的控制器和操作。相反，我认为你想指向Griddler的控制器和行动。见“安装”下的自述。

将您的routes.rb更改为：

# your own route
# post '/email_processor' => 'fax#sendgrid'

# griddler's
post '/email_processor' => 'griddler/emails#create'

如果你是看看Griddler的控制器，你会发现有几件事情可以让你把东西放到你的电子邮件处理器类中。

Answer 2

我在Rails中这样做的方法是在Controller中收集电子邮件params。

例如，在我创建的一个示例应用程序中，人们通过电子邮件自拍我们的Parse。在我的selfie_controller.rb中，我有一个路由‘/入站’，并且我有以下内容：

def inbound

    if !params['attachment1'].nil? and params['attachment1'].content_type == "image/jpeg"

        Selfy.create!({ pic: params['attachment1'], email: params['from'] })

    end

end

给Selfy.create的电话！使用selfy.rb模型，但我收集电子邮件中的params发送到控制器。

你能试试这个吗？