我对AngularJS相当陌生,我想要创建一个条件显示,因为如果我的系统中的一个文件没有属性,它将显示“这个文件没有属性”
我的html当前如下:
<div>
<br />
<ul class="list-unstyled">
<li ng-repeat="fileInfo in fileResources">
<div class="panel panel-default">
<div class="panel-heading">
<span class="label label-default">{{fileInfo.DocType}}</span>
<span class="panel-title">{{fileInfo.Name}}</span>
</div>
<div class="panel-body">
<div class="panel panel-info" ng-if="fileInfo.fileAttributes">
<div class="panel-heading">file Attributes</div>
<div class="panel-body">
<ac-file-attributes
file-attributes="fileInfo.fileAttributes"
display-options="displayOptions">
</ac-file-attributes>
</div>
</div>
<div class="panel panel-info" ng-if="fileInfo.PhysicalProperties" >
<div class="panel-heading">Physical Properties</div>
<div class="panel-body">
<ac-physical-properties
phys-props="fileInfo.PhysicalProperties"
display-options="displayOptions">
</ac-physical-properties>
</div>
</div>
</div>
</div>
</li>
</ul>
</div>发布于 2015-09-09 11:30:59
如果上面的代码已经工作了,那么可以假定您可以使用下面的代码,这只是“不”fileInfo.fileAttributes
<div class="panel panel-info" ng-if="!fileInfo.fileAttributes">
<div class="panel-heading">file Attributes</div>
<div class="panel-body">
<ac-file-attributes
file-attributes="fileInfo.fileAttributes"
display-options="displayOptions">
</ac-file-attributes>
</div>https://stackoverflow.com/questions/32478126
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