中的静态关键字抛出错误

Question

我试着把下面的代码转到试试看标签上-

    class aboutController{
      constructor(ajaxService){
        this.ajaxService = ajaxService;
        this.printLog();
      }

      printLog(){
        this.ajaxService.log();
      }

      static $inject = ["ajaxService"];
    }

静态关键字被转换为

{
  key: "$inject",
  value: ["ajaxService"],
  enumerable: true
}

然后，我尝试了咕噜-巴贝尔任务，以自动化的构建。我的gruntfile.js是这样的-

module.exports = function(grunt){
grunt.initConfig({
    pkg: grunt.file.readJSON('package.json'),
    babel: {
        options: {
            sourceMap: true,
            highlightCode: true
        },
        es6: {
            files: [
                {
                    expand: true,
                    src: ['components/**/*.es6'],
                    ext: '.js'
                }
            ]
        }
    },
    watch: {
        scripts: {
            files: ['components/**/*.es6'],
            tasks:['babel']
        }
    }
});

require("load-grunt-tasks")(grunt);
grunt.registerTask("default", ["babel", "watch"]);
}

但是现在静态关键字给出了错误，当我移除静态关键字时，构建正在传递。知道怎么解决这个问题吗。咕噜-巴贝尔过时了吗？

我的packahe.json是这样的-

{
"name": "babeles6",
"version": "1.0.0",
"description": "",
"main": "index.js",
"scripts": {
    "test": "echo \"Error: no test specified\" && exit 1"
},
"author": "",
"license": "ISC",
"devDependencies": {
    "grunt": "~0.4.2",
    "grunt-babel": "^5.0.1",
    "grunt-contrib-watch": "^0.6.1",
    "load-grunt-tasks": "^3.2.0"
}
}

Answer 1

ES6类语法只支持方法。您的示例使用ES7-建议的类属性。如果您检查了“实验”，则在Babel中启用“试试看”。

 static $inject = ["ajaxService"];

只有当您专门启用es7.classProperties或广泛启用所有阶段0转换时，才能工作。

与ES6兼容的方法将是

static get $inject(){
    return ["ajaxService"];
}