是否有一种方法强迫C#枚举只接受几个显式命名常量中的一个,还是有另一个特性可以接受?C#引用有这样的事后考虑:
可以将任意整数值赋值给枚举类型。但是,您不应该这样做,因为隐含的期望是枚举变量将只保存枚举定义的一个值。将任意值赋值给枚举类型的变量将带来错误的高风险。
(设计了一种新的语言,允许这种草率。)这让我很困惑。)
发布于 2015-09-06 00:05:21
据我所知,您无法阻止C#允许在枚举和整数之间进行转换。
作为解决办法,您可以使用带有受限实例化的自定义类型。用法将类似,但您也将有机会为这种类型定义方法和运算符。
就说你有这件事:
enum DayOfWeek
{
Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
}你可以用一个密封的类代替它。优点是免费获得比较(因为在这种情况下,值比较和引用比较是等价的)。缺点是(与C#中的所有引用类型一样),它是可空的。
sealed class DayOfWeek
{
public static readonly DayOfWeek Monday = new DayOfWeek(0);
public static readonly DayOfWeek Tuesday = new DayOfWeek(1);
public static readonly DayOfWeek Wednesday = new DayOfWeek(2);
public static readonly DayOfWeek Thursday = new DayOfWeek(3);
public static readonly DayOfWeek Friday = new DayOfWeek(4);
public static readonly DayOfWeek Saturday = new DayOfWeek(5);
public static readonly DayOfWeek Sunday = new DayOfWeek(6);
private readonly int _value;
private DayOfWeek(int value)
{
_value = value;
}
}或者你可以用一个结构。它的优点是它不能为空,因此它甚至更类似于枚举。缺点是您必须手动实现比较代码:
struct DayOfWeek
{
public static readonly DayOfWeek Monday = new DayOfWeek(0);
public static readonly DayOfWeek Tuesday = new DayOfWeek(1);
public static readonly DayOfWeek Wednesday = new DayOfWeek(2);
public static readonly DayOfWeek Thursday = new DayOfWeek(3);
public static readonly DayOfWeek Friday = new DayOfWeek(4);
public static readonly DayOfWeek Saturday = new DayOfWeek(5);
public static readonly DayOfWeek Sunday = new DayOfWeek(6);
private readonly int _value;
private DayOfWeek(int value)
{
_value = value;
}
public bool Equals(DayOfWeek other)
{
return _value == other._value;
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj))
{
return false;
}
return obj is DayOfWeek && Equals((DayOfWeek)obj);
}
public override int GetHashCode()
{
return _value;
}
public static bool operator ==(DayOfWeek op1, DayOfWeek op2)
{
return op1.Equals(op2);
}
public static bool operator !=(DayOfWeek op1, DayOfWeek op2)
{
return !(op1 == op2);
}
}发布于 2015-09-06 00:02:35
将任何整数强制转换为枚举的能力主要是由于性能原因,但作为值类型实现的枚举不能保护其不包含未定义的值。考虑一种类似于:
public enum Condition {
Right = 1,
Wrong = 2
}即使枚举变量的赋值仅限于定义的值,您仍然可以通过简单地将其放入类中来创建未定义的值:
public class Demo {
public Condition Cond;
}当创建类的实例时,成员被初始化为零,因此Cond成员变量将具有未定义的(Condition)0值。
您可以创建一个包装类,以确保枚举值在定义的值中:
public sealed class SafeEnum<T> where T : struct {
public T Value { get; private set; }
public SafeEnum(T value) {
if (!(value is Enum)) {
throw new ArgumentException("The type is not an enumeration.");
}
if (!Enum.IsDefined(typeof(T), value)) {
throw new ArgumentException("The value is not defined in the enumeration.");
}
Value = value;
}
}示例:
var cond = new SafeEnum<Condition>(Condition.Right); // works
Condition d = cond.Value;
var cond = new SafeEnum<int>(42); // not an enum
var cond = new SafeEnum<Condition>((Condition)42); // not defined类的实例只能包含在枚举中定义的值,否则构造函数将不允许创建实例。
由于类是不可变的,因此值不能更改为未定义的值。
https://stackoverflow.com/questions/32418634
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