在SubClass中打印SuperClass中的所有SuperClass，在SubClass中打印所有SuperClass

Question

我想在SuperClass中打印所有的subClasses，在subClasses中打印所有的SuperClasses：

class SuperClass():
    def Print(self):
        print('my sub classes are : ')
        #print all childs

class Sub1(SuperClass,...):
    def Print(self):
        print('My parents are :')
        #print all SuperClasses

class Sub2(SuperClass,...):
    def Print(self):
        print('My parents are :')
        #print all SuperClasses

SuperClass有打印所有继承类的打印，Sub有打印所有SuperClasses的打印方法。怎么做到的？

Answer 1

Python类有三个属性在这里提供帮助：

• class.__subclasses__()；返回类的所有子类的方法。
• class.__bases__是当前类的直接父类的元组。
• class.__mro__，一个包含当前类层次结构中所有类的元组。在这个元组中查找当前类对象，下面的所有内容都是一个父类，直接或间接。

使用这些可以提供：

class SuperClass(object):
    def print(self):
        print('my sub classes are:', ', '.join([
            cls.__name__ for cls in type(self).__subclasses__()]))

class Sub1(SuperClass):
    def print(self):
        print('My direct parents are:', ', '.join([
            cls.__name__ for cls in type(self).__bases__]))
        all_parents = type(self).__mro__
        all_parents = all_parents[all_parents.index(Sub1) + 1:]
        print('All my parents are:', ', '.join([
            cls.__name__ for cls in all_parents]))

演示：

>>> SuperClass().print()
my sub classes are: Sub1
>>> Sub1().print()
My direct parents are: SuperClass
All my parents are: SuperClass, object