茉莉花吞咽，运行测试上的测试文件更改

Question

嗨，我想要做的是用watcher task来运行我的茉莉测试。我到目前为止所做的事：

var watch = require("gulp-watch");
var jasmine = require("gulp-jasmine");

gulp.task('tests.run.change-watcher', function (cb) {
    gulp.src(testsFiles)
        .pipe(watch(testsFiles))
        .pipe(jasmine({ verbose: true }));
});

但是，当我运行该任务并试图更改任何符合testsFiles规则的文件时，它不会在控制台中显示任何内容。

但是，当我运行下一个任务时：

gulp.task('tests.run', function (cb) {
    gulp.src(testsFiles)
        .pipe(jasmine({verbose:true}));
});

它的工作原理和接下来的演示：8 specs, 0 failures Finished in 0 seconds

也许我错过了什么？

Answer 1

要运行只需要的规范，请尝试如下所示：

/** Watches file changes in source or spec files and executes specs automatically */
gulp.task("specs-watcher", function() {
  return watch(["src/**/*.ts", "spec/**/*.ts"], { events: ["add", "change"] }, function(vinyl, event) {
    if (!vinyl.isDirectory()) {
      if (vinyl.basename.endsWith(".spec.ts")) {
        // We are dealing with a spec file here, so call jasmine!
        runJasmine(vinyl.path);
      } else {
        // Try to find out specs file
        const specFilePath = findSpecsFile(vinyl);
        if (typeof specFilePath === "string") {
          runJasmine(specFilePath);
        }
      }
    }
  });
});

这个观察者使用两个函数，一个是根据文件名派生规范名称。就我而言，它是：

/**
 * For your specs-watcher: This function is called every time a file changed which doesn't end with '.spec.ts'.
 * The function's task is to return the fitting specs path of this file. For example by looking for a corresponding file in the "/spec/" folder.
 * @param {vinyl} changedFile Vinyl object of changed file (see https://github.com/gulpjs/vinyl)
 * @return {string|undefined} Path to the specs file to execute or undefined if your watcher shouldn't do anything.
 */
function findSpecsFile(changedFile) {
  return changedFile.path.replace(__dirname, `${__dirname}/spec`).replace(".ts", ".spec.ts");
}

另一个函数是runJasmine，它使用给定的测试文件运行茉莉。

只要让一切都适合你的设置，它应该可以工作。:-)

Answer 2

分两步做

1)声明测试单元任务(就像您所做的那样)

gulp.task('tests.run', function () {
    return gulp.src(testsFiles)
        .pipe(jasmine({verbose:true}));
});

2)声明当这些testsFiles更改时将运行此测试单元任务的监视任务。

gulp.task('tests.watch', function () {
    gulp.watch(testsFiles, ['tests.run']);
});

然后，运行gulp tests.watch

Answer 3

您可以通过以下方式侦听测试和源代码文件夹的文件更改：

"use strict";

var gulp = require('gulp');
var mocha = require('gulp-mocha');
var batch = require('gulp-batch');

gulp.watch(['tests/**', 'src/**'], batch(function (events, cb) {
    return gulp.src(['tests/*.js'])
        .pipe(jasmine({ verbose: true }))
        .on('error', function (err) {
            console.log(err.stack);
        });
}));

gulp.task('default', () => {
    console.log('Gulp is watching file changes...');
});