带有Where子句的Linq到json过滤结果

Question

我对json很陌生。我试图在C#中使用linq过滤json数据到json查询。我试图从json数据中检索多个值：

string json= @"{
 "parts": [
    {

      "attributes": {
        "Motherboard": "Gigabyte GA-H81M-S2H",
        "Max RAM": "16GB",
        "Form Factor": "Micro ATX",
        "RAM Slots": 2,
        "Socket / CPU": "LGA1150"
      },
      "type": "Motherboard",
      "name": "Gigabyte GA-H81M-S2H",
      "slug": "gigabyte-motherboard-gah81ms2h"
    },
    {
        "attributes": {
        "Motherboard": "MSI H55-G43",
        "Max RAM": "16GB",
        "Form Factor": "ATX",
        "RAM Slots": 4,
        "Socket / CPU": "LGA1156"
      },
      "type": "Motherboard",
      "name": "MSI H55-G43",
      "slug": "msi-motherboard-h55g43"
    },
    {
      "url": "http://pcpartpicker.com/part/asus-motherboard-rampageivblackedition",
      "attributes": {
        "Motherboard": "Asus Rampage IV Black Edition",
        "Max RAM": "128GB",
        "Form Factor": "EATX",
        "RAM Slots": 8,
        "Socket / CPU": "LGA2011"
      },
      "type": "Motherboard",
      "name": "Asus Rampage IV Black Edition",
      "slug": "asus-motherboard-rampageivblackedition"
    }
 ],

}";

这是我的C#代码：

JObject results = JObject.Parse(json);
  var categories = from c in results["parts"]["attributes"].Children()["Motherboard"].Values<string>()
                         group c by c
                         into g
                         orderby g.Count() descending
                         select new { Category = g.Key, Count = g.Count() };

我试过使用这段代码，它不返回任何result.Please，让我知道我做错了什么，或者这是编写query.Can的正确方法，请任何人帮助我解决这个问题。

Answer 1

您可以使用SelectTokens进行这种性质的查询。它支持JSONPath查询语法。因此：

        var categories = from c in results.SelectTokens("parts[*].attributes.Motherboard")
                         group c by c
                             into g
                             orderby g.Count() descending
                             select new { Category = (string)g.Key, Count = g.Count() };

在JSON中，"parts" : [...]的值是一个数组；在查询中，"parts[*]"是一个通配符，它搜索数组的所有元素。