我有一个包含一些损坏记录的表,因为我忘记为两个列添加一个UNIQUE索引。请看下表中的示例:
+----+-------------+--------+------------+
| id | uuid | object | project_id |
+----+-------------+--------+------------+
| 1 | 73621000001 | screw | 1 |
| 2 | 73621000002 | screw | 1 |
| 3 | 73621000003 | screw | 1 |
| 4 | 73621000004 | tube | 1 |
| 5 | 73621000005 | plate | 2 |
| 6 | 73621000006 | plate | 2 |
| 7 | 73621000007 | plate | 2 |
| 8 | 73621000008 | plate | 2 |
| 9 | 73621000009 | plate | 2 |
| 10 | 73621000010 | gear | 4 |
| 11 | 73621000011 | gear | 4 |
+----+-------------+--------+------------+如您所见,有一些object-project_id-combinations多次发生,但有不同的uuids。我想删除所有重复的记录,但保留那些最高的uuid。由此产生的表格应如下:
+----+-------------+--------+------------+
| id | uuid | object | project_id |
+----+-------------+--------+------------+
| 3 | 73621000003 | screw | 1 |
| 4 | 73621000004 | tube | 1 |
| 9 | 73621000009 | plate | 2 |
| 11 | 73621000011 | gear | 4 |
+----+-------------+--------+------------+我可以使用以下查询查看哪些object具有重复项:
SELECT uuid, object, project_id, COUNT(*)
FROM uuid_object_mapping
GROUP BY object, project_id
HAVING COUNT(*) > 1;我可以使用以下查询获得“干净”表:
SELECT MAX(uuid) as uuid, object, project_id
FROM uuid_object_mapping
GROUP BY object, project_id;并且我可以验证“干净”表没有包含重复的
SELECT uuid, object, project_id, COUNT(*)
FROM (
SELECT MAX(uuid) as uuid, object_name, project_id
FROM uuid_object_mapping
GROUP BY object_name, project_id
) AS clean
GROUP BY object_name, project_id
HAVING COUNT(*) > 1;但是,我如何删除所有不在“干净”表中的内容?
发布于 2015-08-21 11:39:40
在MySQL中,您可以使用join,但是您需要注意NULL值:
delete om
from uuid_object_mapping om join
(select MAX(uuid) as uuid, object, project_id
from uuid_object_mapping
group by object, project_id
) omkeep
on omkeep.object = om.object and
omkeep.project_id <=> om.project_id
where om.uuid <> omkeep.uuid;NULL值似乎已经消失,因此可以使用以下on子句:
on omkeep.object = om.object and
omkeep.project_id = om.project_id发布于 2015-08-21 11:54:17
请使用分区和顺序uuid子句。通过搜索分析。这是去除重复的最佳方法。
发布于 2015-08-21 11:37:45
尝尝这个
select t1.id,t1.uuid,t1.object,t1.project_id from table as t1 inner join
(
select object,max(id) as id from table
group by object
) as t2 on t1.object=t2.object and t1.id=t2.idhttps://stackoverflow.com/questions/32139297
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