我想要生成由标签和图标组成的图像。标签部分将有很多变化(50-100),而有大约10个图标。我想通过将最终图像分割成两个部分,一个标签图像和一个图标图像,以模块化的方式制作最终图像。我将构建一个为标签返回dataURI的服务,而图标数据for将嵌入到页面中。然后,我想将这两个不同的数据two组合起来,创建一个表示组合图像的单个dataURI。
我怎样才能在客户端做到这一点?
发布于 2015-08-20 12:24:45
您可以使用数据uris创建图像,然后使用canvas绘制包含它们的新映像。下面是一个简单的例子:
var nloaded = 0;
function checkload(event) {
nloaded++;
if (nloaded < 2) {
return;
}
var canvas = document.querySelector('canvas');
var context = canvas.getContext('2d');
context.drawImage(image1, 0, 0, 50, 50);
context.drawImage(image2, 50, 50, 100, 100);
var combined = new Image;
combined.src = canvas.toDataURL('data/gif');
document.body.appendChild(combined);
}
var image1 = new Image;
image1.onload = checkload;
image1.src = 'data:image/gif;base64,R0lGODdhAgACALMAAAAAAP///wAAAAAAAP8AAAAAAAAAAAAAAAAA/wAAAAAAAAAAAAAAAAAAAAAAAAAAACwAAAAAAgACAAAEAxBJFAA7';
var image2 = new Image;
image2.onload = checkload;
image2.src = 'data:image/gif;base64,R0lGODdhAgACALMAAAAAAP///wAAAAAAAP8AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACwAAAAAAgACAAAEA5BIEgA7';canvas {
display: none;
}<canvas width=100 height=100></canvas>
。
一旦从数据URI加载了图像并使用画布上下文的drawImage命令组合,就可以使用画布创建如下所示的新映像:
var combined = new Image;
combined.src = canvas.toDataURL('data/gif');不幸的是,这在IE8中行不通。
发布于 2018-06-02 16:02:41
示例使用包含URI src和x,y偏移量的图像对象数组:
var images = [
{ src: 'data:image/gif;base64,R0lGODdhAgACALMAAAAAAP///wAAAAAAAP8AAAAAAAAAAAAAAAAA/wAAAAAAAAAAAAAAAAAAAAAAAAAAACwAAAAAAgACAAAEAxBJFAA7', x: 0, y: 0 },
{ src: 'data:image/gif;base64,R0lGODdhAgACALMAAAAAAP///wAAAAAAAP8AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACwAAAAAAgACAAAEA5BIEgA7', x: 20, y: 20 },
];
var canvas = document.createElement('canvas');
var destination = document.getElementById('canvas');
Promise.all(images.map(imageObj => add2canvas(canvas, imageObj)))
.then(() => destination.append(canvas));
function add2canvas(canvas, imageObj) {
return new Promise( (resolve, reject) => {
if (!imageObj || typeof imageObj != 'object') return reject();
var image = new Image();
image.onload = function () {
canvas.getContext('2d')
.drawImage(this, imageObj.x || 0, imageObj.y || 0);
resolve();
};
image.src = imageObj.src;
});
}更多的铃铛/口哨..。函数生成复合png:
function mergeImageURIs(images) {
return new Promise( (resolve, reject) => {
var canvas = document.createElement('canvas');
canvas.width = 1000; // desired width of merged images
canvas.height = 1000; // desired height of merged images
Promise.all(images.map(imageObj => add2canvas(canvas, imageObj))).then(() => resolve(canvas.toDataURL('image/png'), reject));
});
}
function add2canvas(canvas, imageObj) {
return new Promise( (resolve, reject) => {
if (!imageObj || typeof imageObj != 'object') return reject();
var x = imageObj.x && canvas.width ? (imageObj.x >=0 ? imageObj.x : canvas.width + imageObj.x) : 0;
var y = imageObj.y && canvas.height ? (imageObj.y >=0 ? imageObj.y : canvas.height + imageObj.y) : 0;
var image = new Image();
image.onload = function () {
canvas.getContext('2d').drawImage(this, x, y);
resolve();
};
image.src = imageObj.src;
});
}https://stackoverflow.com/questions/32096540
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