Python列表更改

Question

我试图将包含有项的数组转换为包含倒置的数组.这是一个糟糕的例子，所以这里基本上是我想要做的事情的概念：

array1 = [["1","2","3"],["4","5","6"],["A","B","C"],["D","E","F"]]
array2 = doSomething(array1) # Do Something To The Array To Get Second:
# In The End I Want The Array To Be:
# array2 = [["1","4","A","D"],["2","5","B","E"],["3","6","C","F"]]

如果这有意义的话..。如果每个数组中的数组和项的数量未知(每个数组的项数相同)，请告诉我您是否知道这样做的方法。

Answer 1

这应该可以做到：

original_list = [
    ['1', '2', '3'],
    ['4', '5', '6'],
    ['A', 'B', 'C'],
    ['D', 'E', 'F']
    ]

new_list = list(zip(*original_list))

print(new_list)

结果：

[('1', '4', 'A', 'D'), ('2', '5', 'B', 'E'), ('3', '6', 'C', 'F')]