正确地将php格式化为html表

Question

我有一个php数组，它包含来自我的数据库$name[] = $row['name']的信息。还有大约3行容器email、age和screen-resolution。

我正试着把它整齐地塞进一张桌子上，看上去像：

name----------email----------age----------screen-res

name1---------email1--------age1---------res1

name2---------email2--------age2---------res2

然而，我目前的情况如下：

name----------email----------age----------screen-res

name1---------name2----------name3------name4---------name5------name6-------name7------name8

email1---------email2----------email3------email---------email5------email6-------email7

我的密码

​

<table>
  <tr>
    <th>Name</th>
    <th>Email</th>
    <th>Age</th>
    <th>Screen-Res</th>
  </tr>
  <?php
    echo "<tr>";
    foreach ($name as $nameVal) {
        echo "<td>$nameVal</td>";
    }
    echo "</tr>";

    echo "<tr>";
    foreach ($email as $emailVal) {
        echo "<td>$emailVal</td>";
    }
    echo "</tr>";

    echo "<tr>";
    foreach ($age as $ageVal) {
        echo "<td>$ageVal</td>";
    }
    echo "</tr>";

    echo "<tr>";
    foreach ($screen-res as $screen-resVal) {
        echo "<td>$screen-resVal</td>";
    }
    echo "</tr>";
  ?>
</table>

​

Answer 1

您的表格式不正确。你的桌子看起来像这样。好的是，对于所有的数据，只需要一个数组。

<table>
  <tr>
    <th>Name</th>
    <th>Email</th>
    <th>Age</th>
    <th>Screen-Res</th>
  </tr>
  <?php

    foreach ($rows as $row) {
        echo "<tr>";
        echo "<td>".$row['nameVal']."</td>";

        echo "<td>".$row['emailVal']."</td>";

        echo "<td>".$row['ageVal']."</td>";

        echo "<td>".$row['screen-resVal']."</td>";
            echo "</tr>";
    }

  ?>
</table>