我正在试验Crossbar.io 0.10.4和Django 1.6.11,试图遵循这里的例子。代码显示您可以将Crossbar.io配置为在"/“上为Django应用提供服务--但是当我在配置中尝试时,我会得到一个Python错误:
ApplicationError: ApplicationError('crossbar.error.invalid_configuration', args = (u"WSGI app module 'apache/django.wsgi' import failed: Import by filename is not supported. - Python search path was ....我的config.json在这里:
{
"controller": {
},
"workers": [
{
"type": "router",
"realms": [
{
"name": "backstage-producer",
"roles": [
{
"name": "anonymous",
"permissions": [
{
"uri": "*",
"publish": false,
"subscribe": true,
"call": false,
"register": false
}
]
}
]
}
],
"transports": [
{
"type": "web",
"endpoint": {
"type": "tcp",
"port": 8080
},
"paths": {
"/": {
"type": "wsgi",
"module": "apache/django.wsgi",
"object": "application"
},
"ws": {
"type": "websocket",
"debug": false
},
"notify": {
"type": "publisher",
"realm": "backstage-producer",
"role": "anonymous"
},
"static": {
"type": "static",
"directory": "../static"
}
}
}
]
}
]
}其中搜索的Python路径不包括my项目目录。通常,我会将特定的项目目录附加到我的wsgi文件中的sys.path中,但显然该工作流不适用于Crossbar.io。尝试相对导入失败(需要指定“包”参数)和完整路径(相同的导入文件名错误与上面一样)。
删除"/“的定义不起作用,因为Crossbar.io抱怨必须定义它。
我如何用Crossbar.io正确地设置它呢?我的apache/django.wsgi文件如下所示,以供参考:
ALLDIRS = ['/usr/local/pythonenv/myapp/lib/python2.6/site-packages']
import os
import sys
import site
# from https://code.google.com/p/modwsgi/wiki/VirtualEnvironments
sys.path.insert(0, '/var/www/myapp/myapp_main/')
sys.path.insert(1, '/var/www/myapp/')
prev_sys_path = list(sys.path)
for directory in ALLDIRS:
site.addsitedir(directory)
new_sys_path = []
for item in list(sys.path):
if item not in prev_sys_path:
new_sys_path.append(item)
sys.path.remove(item)
sys.path[:0] = new_sys_path
os.environ['DJANGO_SETTINGS_MODULE'] = 'myapp_main.settings'
import django.core.handlers.wsgi
application = django.core.handlers.wsgi.WSGIHandler()-更新1
根据丹尼尔的建议,我将文件更改为wsgi.py,并将配置更改为使用Python模块路径,而不是文件名/目录路径。然后,配置如下所示:
"paths": {
"/": {
"type": "wsgi",
"module": "apache.wsgi",
"object": "application"
},抛出相同的异常:
ApplicationError: ApplicationError('crossbar.error.invalid_configuration', args = (u"WSGI app module 'apache.wsgi' import failed: No module named apache.wsgi - Python search path was我的目录结构是:
Project
|- apache
| |-__init__.py
| |-wsgi.py
|-.crossbar
|-config.json 更新2
我找到的唯一解决方案(读"hack")是将我的项目路径硬编码到crossbar/worker/router.py中,以便将其包含在Python列表中:
sys.path.insert(0, '/var/www/myapp/myapp_main/')
sys.path.insert(1, '/var/www/myapp/')看来应该有更好的办法..。
发布于 2015-08-10 20:24:57
错误告诉您,设置中有指向WSGI文件的文件路径,而需要Python模块路径。您的WSGI文件实际上应该是项目目录中的一个名为"wsgi.py“的文件(大概是"apache",它是一个显式不使用Apache的项目的奇怪名称)。
"/": {
"type": "wsgi",
"module": "apache.wsgi",
"object": "application"
},更新了,所以我终于找到了配置文档:他们真的不费吹灰之力让它变得简单,比如实际上提供了一个索引。哦,好吧。
看起来您可以为路由器配置提供一个options哈希,包括一个pythonpath设置:
"workers": [
{
"type": "router",
"options": {
"pythonpath": ["/var/myapp/myapp_main/", "/var/myapp"]
},
...
"transports": {
...https://stackoverflow.com/questions/31928328
复制相似问题