在JXTreeTable中替换和刷新旧的ScrollPane

Question

我在滚动窗格(gbc_constraints)中有一个gbc_constraints，通过单击按钮，文件选择器窗口应该打开，然后用户选择一个JxTreeTable文件，该文件应该被解析为一个新的JxTreeTable。我想用新的代替旧的。但我在努力让这些变化变得显而易见。程序不会明显地调整树，也不会刷新或重新绘制树。我希望你能帮助我。

public class pnlXMLTree extends JPanel {

     public TreeTable treeTable;
     public JScrollPane scrollPane;
     public JXTreeTable jxttable;
     public pnlXMLTree() {
            List<Object[]> content = new ArrayList<>();
            final JFileChooser fc = new JFileChooser();
            treeTable = new TreeTable(content);
            ....
            jxttable = treeTable.getTreeTable();
            scrollPane = new JScrollPane(jxttable);
            GridBagConstraints gbc_scrollPane = new GridBagConstraints();
            gbc_scrollPane.anchor = GridBagConstraints.NORTH;
            gbc_scrollPane.fill = GridBagConstraints.HORIZONTAL;
            gbc_scrollPane.gridwidth = 5;
            gbc_scrollPane.gridheight = 13;
            gbc_scrollPane.gridx = 2;
            gbc_scrollPane.gridy = 1;
            add(scrollPane, gbc_scrollPane);
            ...
            ...

            btnOpenXML.addActionListener(new ActionListener() {
                public void actionPerformed(ActionEvent arg0) {

                    FileNameExtensionFilter xmlfilter = new FileNameExtensionFilter(
                             "xml files (*.xml)", "xml");
                    fc.setFileFilter(xmlfilter);
                    fc.setDialogTitle("Open schedule file");
                    // set selected filter
                    fc.setFileFilter(xmlfilter);
                    int returnVal = fc.showOpenDialog(null);
                    String filepath;
                    if (returnVal == JFileChooser.APPROVE_OPTION) {
                        File file = fc.getSelectedFile();
                        //This is where a real application would open the file.
                        System.out.println("Opening: " + file.getName() + ".");
                        filepath = file.getAbsolutePath();
                        jxttable = treeTable.getTreeTable(filepath);
                        //scrollPane = new JScrollPane(treeTable.getTreeTable(filepath));
                        //jxttable.getModel().getRow(0).;

                    } else {
                        System.out.println("Open command cancelled by user.");
                    }


                }
            });

        setVisible(true);

     }

 }

Answer 1

对于JXTreeTable，我总是有同样的问题，解决方案似乎是像这样重置模型：

myTree.setTreeTableModel(new MyTreeTableModel(rootNode));

在这个例子中，我的模型构造器以TreeNode类型的根树节点作为参数。