我在Linux操作系统+ ARM处理器+ boost 1.51上运行以下代码。但是,代码没有按预期工作,timed_wait()调用立即返回。
#include <boost/thread/condition.hpp>
#include <boost/thread/xtime.hpp>
#include <boost/thread/mutex.hpp>
#include <iostream>
using namespace std;
int main()
{
boost::mutex mutex_;
boost::mutex::scoped_lock lock( mutex_ );
boost::xtime xt;
boost::condition condition;
// wait for one second or wait on lock
boost::xtime_get(&xt, boost::TIME_UTC_);
xt.sec += 1;
cout << "Before 1 second wait" << endl;
condition.timed_wait(lock, xt);
cout << "After 1 second wait" << endl;
return 0;
}在具有相同ARM处理器但不同版本的Linux + glibc +相同boost 1.51库的其他系统上,代码工作正常,等待1秒。
我试着用strace调试这个问题。在对futex()的调用不起作用的系统中,我看到了一个不同的地方。
来自代码正在工作的系统的字符串:
write(1, "Before 1 second wait\n", 21Before 1 second wait) = 21
futex(0xb6fbf0dc, FUTEX_WAKE_PRIVATE, 2147483647) = 0
clock_gettime(CLOCK_REALTIME, {1438150496, 732211544}) = 0
futex(0xbef07a44, FUTEX_WAIT_PRIVATE, 1, {0, 998193456}) = -1 ETIMEDOUT (Connection timed out)
futex(0xbef07a28, FUTEX_WAKE_PRIVATE, 1) = 0
write(1, "After 1 second wait\n", 20After 1 second wait) = 20从代码不起作用的系统中捕获:
write(1, "Before 1 second wait\n", 21Before 1 second wait) = 21
futex(0xb6fc90dc, FUTEX_WAKE_PRIVATE, 2147483647) = 0
clock_gettime(CLOCK_REALTIME, {1438150407, 134963583}) = 0
futex(0xbe9be988, FUTEX_WAKE_PRIVATE, 1) = 0
write(1, "After 1 second wait\n", 20After 1 second wait) = 20是否需要对内核/ glibc进行更改以使代码正常工作?
发布于 2015-07-29 08:55:10
为什么不使用一个实际的超时,而不是在使用超时时使用时钟呢?
condition.timed_wait(lock,boost::posix_time::milliseconds(1000))这就防止了所有奇怪的问题。
https://stackoverflow.com/questions/31695487
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