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调整C中现有的GOST代码以散列文件
EN

Stack Overflow用户
提问于 2015-07-21 19:49:22
回答 3查看 197关注 0票数 1

我正在尝试使用C对GOST哈希函数进行手工编码。我看到了Markku-Juhani (来自链接)的以下代码。

代码语言:javascript
复制
/*
 *  gosthash.c 
 *  21 Apr 1998  Markku-Juhani Saarinen <mjos@ssh.fi>
 * 
 *  GOST R 34.11-94, Russian Standard Hash Function
 *
 *  Copyright (c) 1998 SSH Communications Security, Finland
 *  All rights reserved.
 */

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "gosthash.h"

/* lookup tables : each of these has two rotated 4-bit S-Boxes */

unsigned long gost_sbox_1[256];
unsigned long gost_sbox_2[256];
unsigned long gost_sbox_3[256];
unsigned long gost_sbox_4[256];

/* initialize the lookup tables */

void gosthash_init()
{
  int a, b, i;
  unsigned long ax, bx, cx, dx;

  /* 4-bit S-Boxes */ 

  unsigned long sbox[8][16] =
    {
    {  4, 10,  9,  2, 13,  8,  0, 14,  6, 11,  1, 12,  7, 15,  5,  3 },
    { 14, 11,  4, 12,  6, 13, 15, 10,  2,  3,  8,  1,  0,  7,  5,  9 },
    {  5,  8,  1, 13, 10,  3,  4,  2, 14, 15, 12,  7,  6,  0,  9, 11 },
    {  7, 13, 10,  1,  0,  8,  9, 15, 14,  4,  6, 12, 11,  2,  5,  3 },
    {  6, 12,  7,  1,  5, 15, 13,  8,  4, 10,  9, 14,  0,  3, 11,  2 },
    {  4, 11, 10,  0,  7,  2,  1, 13,  3,  6,  8,  5,  9, 12, 15, 14 },
    { 13, 11,  4,  1,  3, 15,  5,  9,  0, 10, 14,  7,  6,  8,  2, 12 },
    {  1, 15, 13,  0,  5,  7, 10,  4,  9,  2,  3, 14,  6, 11,  8, 12 }  
    };

  /* s-box precomputation */

  i = 0;
  for (a = 0; a < 16; a++)
    {
      ax = sbox[1][a] << 15;      
      bx = sbox[3][a] << 23;
      cx = sbox[5][a];        
      cx = (cx >> 1) | (cx << 31);
      dx = sbox[7][a] << 7;

      for (b = 0; b < 16; b++)
    {
      gost_sbox_1[i] = ax | (sbox[0][b] << 11);       
      gost_sbox_2[i] = bx | (sbox[2][b] << 19);
      gost_sbox_3[i] = cx | (sbox[4][b] << 27);   
      gost_sbox_4[i++] = dx | (sbox[6][b] << 3);
    }
    }
}

/*
 *  A macro that performs a full encryption round of GOST 28147-89.
 *  Temporary variable t assumed and variables r and l for left and right
 *  blocks
 */ 

#define GOST_ENCRYPT_ROUND(k1, k2) \
t = (k1) + r; \
l ^= gost_sbox_1[t & 0xff] ^ gost_sbox_2[(t >> 8) & 0xff] ^ \
gost_sbox_3[(t >> 16) & 0xff] ^ gost_sbox_4[t >> 24]; \
t = (k2) + l; \
r ^= gost_sbox_1[t & 0xff] ^ gost_sbox_2[(t >> 8) & 0xff] ^ \
gost_sbox_3[(t >> 16) & 0xff] ^ gost_sbox_4[t >> 24]; \

/* encrypt a block with the given key */

#define GOST_ENCRYPT(key) \
GOST_ENCRYPT_ROUND(key[0], key[1]) \
GOST_ENCRYPT_ROUND(key[2], key[3]) \
GOST_ENCRYPT_ROUND(key[4], key[5]) \
GOST_ENCRYPT_ROUND(key[6], key[7]) \
GOST_ENCRYPT_ROUND(key[0], key[1]) \
GOST_ENCRYPT_ROUND(key[2], key[3]) \
GOST_ENCRYPT_ROUND(key[4], key[5]) \
GOST_ENCRYPT_ROUND(key[6], key[7]) \
GOST_ENCRYPT_ROUND(key[0], key[1]) \
GOST_ENCRYPT_ROUND(key[2], key[3]) \
GOST_ENCRYPT_ROUND(key[4], key[5]) \
GOST_ENCRYPT_ROUND(key[6], key[7]) \
GOST_ENCRYPT_ROUND(key[7], key[6]) \
GOST_ENCRYPT_ROUND(key[5], key[4]) \
GOST_ENCRYPT_ROUND(key[3], key[2]) \
GOST_ENCRYPT_ROUND(key[1], key[0]) \
t = r; \
r = l; \
l = t;

/* 
 *  "chi" compression function. the result is stored over h
 */

void gosthash_compress(unsigned long *h, unsigned long *m)
{
  int i;
  unsigned long l, r, t, key[8], u[8], v[8], w[8], s[8];

  memcpy(u, h, sizeof(u));
  memcpy(v, m, sizeof(u));

  for (i = 0; i < 8; i += 2)
    {        
      w[0] = u[0] ^ v[0];          /* w = u xor v */
      w[1] = u[1] ^ v[1];
      w[2] = u[2] ^ v[2];
      w[3] = u[3] ^ v[3];
      w[4] = u[4] ^ v[4];
      w[5] = u[5] ^ v[5];
      w[6] = u[6] ^ v[6];
      w[7] = u[7] ^ v[7];      

      /* P-Transformation */

      key[0] = (w[0]  & 0x000000ff) | ((w[2] & 0x000000ff) << 8) |
    ((w[4] & 0x000000ff) << 16) | ((w[6] & 0x000000ff) << 24);
      key[1] = ((w[0] & 0x0000ff00) >> 8)  | (w[2]  & 0x0000ff00) |
    ((w[4] & 0x0000ff00) << 8) | ((w[6] & 0x0000ff00) << 16);
      key[2] = ((w[0] & 0x00ff0000) >> 16) | ((w[2] & 0x00ff0000) >> 8) |
    (w[4] & 0x00ff0000) | ((w[6] & 0x00ff0000) << 8);
      key[3] = ((w[0] & 0xff000000) >> 24) | ((w[2] & 0xff000000) >> 16) |
    ((w[4] & 0xff000000) >> 8) | (w[6] & 0xff000000);  
      key[4] = (w[1] & 0x000000ff) | ((w[3] & 0x000000ff) << 8) |
    ((w[5] & 0x000000ff) << 16) | ((w[7] & 0x000000ff) << 24);
      key[5] = ((w[1] & 0x0000ff00) >> 8) | (w[3]  & 0x0000ff00) |
    ((w[5] & 0x0000ff00) << 8) | ((w[7] & 0x0000ff00) << 16);
      key[6] = ((w[1] & 0x00ff0000) >> 16) | ((w[3] & 0x00ff0000) >> 8) |
    (w[5] & 0x00ff0000) | ((w[7] & 0x00ff0000) << 8);
      key[7] = ((w[1] & 0xff000000) >> 24) | ((w[3] & 0xff000000) >> 16) |
    ((w[5] & 0xff000000) >> 8) | (w[7] & 0xff000000);  

      r = h[i];                /* encriphering transformation */
      l = h[i + 1];      
      GOST_ENCRYPT(key);

      s[i] = r;
      s[i + 1] = l;

      if (i == 6)
    break;

      l = u[0] ^ u[2];             /* U = A(U) */
      r = u[1] ^ u[3];
      u[0] = u[2];
      u[1] = u[3];
      u[2] = u[4];
      u[3] = u[5];
      u[4] = u[6];
      u[5] = u[7];
      u[6] = l;
      u[7] = r;

      if (i == 2)              /* Constant C_3 */
    {
      u[0] ^= 0xff00ff00; 
      u[1] ^= 0xff00ff00; 
      u[2] ^= 0x00ff00ff;
      u[3] ^= 0x00ff00ff;
      u[4] ^= 0x00ffff00;
      u[5] ^= 0xff0000ff;
      u[6] ^= 0x000000ff;
      u[7] ^= 0xff00ffff;       
    }

      l = v[0];                /* V = A(A(V)) */
      r = v[2];
      v[0] = v[4];
      v[2] = v[6];
      v[4] = l ^ r;
      v[6] = v[0] ^ r;
      l = v[1];
      r = v[3];
      v[1] = v[5];
      v[3] = v[7];
      v[5] = l ^ r;
      v[7] = v[1] ^ r;
    }

  /* 12 rounds of the LFSR (computed from a product matrix) and xor in M */

  u[0] = m[0] ^ s[6];
  u[1] = m[1] ^ s[7];
  u[2] = m[2] ^ (s[0] << 16) ^ (s[0] >> 16) ^ (s[0] & 0xffff) ^ 
    (s[1] & 0xffff) ^ (s[1] >> 16) ^ (s[2] << 16) ^ s[6] ^ (s[6] << 16) ^
    (s[7] & 0xffff0000) ^ (s[7] >> 16);
  u[3] = m[3] ^ (s[0] & 0xffff) ^ (s[0] << 16) ^ (s[1] & 0xffff) ^ 
    (s[1] << 16) ^ (s[1] >> 16) ^ (s[2] << 16) ^ (s[2] >> 16) ^
    (s[3] << 16) ^ s[6] ^ (s[6] << 16) ^ (s[6] >> 16) ^ (s[7] & 0xffff) ^ 
    (s[7] << 16) ^ (s[7] >> 16);
  u[4] = m[4] ^ 
    (s[0] & 0xffff0000) ^ (s[0] << 16) ^ (s[0] >> 16) ^ 
    (s[1] & 0xffff0000) ^ (s[1] >> 16) ^ (s[2] << 16) ^ (s[2] >> 16) ^
    (s[3] << 16) ^ (s[3] >> 16) ^ (s[4] << 16) ^ (s[6] << 16) ^ 
    (s[6] >> 16) ^(s[7] & 0xffff) ^ (s[7] << 16) ^ (s[7] >> 16);
  u[5] = m[5] ^ (s[0] << 16) ^ (s[0] >> 16) ^ (s[0] & 0xffff0000) ^
    (s[1] & 0xffff) ^ s[2] ^ (s[2] >> 16) ^ (s[3] << 16) ^ (s[3] >> 16) ^
    (s[4] << 16) ^ (s[4] >> 16) ^ (s[5] << 16) ^  (s[6] << 16) ^ 
    (s[6] >> 16) ^ (s[7] & 0xffff0000) ^ (s[7] << 16) ^ (s[7] >> 16);
  u[6] = m[6] ^ s[0] ^ (s[1] >> 16) ^ (s[2] << 16) ^ s[3] ^ (s[3] >> 16) ^
    (s[4] << 16) ^ (s[4] >> 16) ^ (s[5] << 16) ^ (s[5] >> 16) ^ s[6] ^ 
    (s[6] << 16) ^ (s[6] >> 16) ^ (s[7] << 16);
  u[7] = m[7] ^ (s[0] & 0xffff0000) ^ (s[0] << 16) ^ (s[1] & 0xffff) ^ 
    (s[1] << 16) ^ (s[2] >> 16) ^ (s[3] << 16) ^ s[4] ^ (s[4] >> 16) ^
    (s[5] << 16) ^ (s[5] >> 16) ^ (s[6] >> 16) ^ (s[7] & 0xffff) ^ 
    (s[7] << 16) ^ (s[7] >> 16);

  /* 16 * 1 round of the LFSR and xor in H */

  v[0] = h[0] ^ (u[1] << 16) ^ (u[0] >> 16);
  v[1] = h[1] ^ (u[2] << 16) ^ (u[1] >> 16);
  v[2] = h[2] ^ (u[3] << 16) ^ (u[2] >> 16);
  v[3] = h[3] ^ (u[4] << 16) ^ (u[3] >> 16);
  v[4] = h[4] ^ (u[5] << 16) ^ (u[4] >> 16);
  v[5] = h[5] ^ (u[6] << 16) ^ (u[5] >> 16);
  v[6] = h[6] ^ (u[7] << 16) ^ (u[6] >> 16);
  v[7] = h[7] ^ (u[0] & 0xffff0000) ^ (u[0] << 16) ^ (u[7] >> 16) ^
    (u[1] & 0xffff0000) ^ (u[1] << 16) ^ (u[6] << 16) ^ (u[7] & 0xffff0000);

  /* 61 rounds of LFSR, mixing up h (computed from a product matrix) */

  h[0] = (v[0] & 0xffff0000) ^ (v[0] << 16) ^ (v[0] >> 16) ^ (v[1] >> 16) ^ 
    (v[1] & 0xffff0000) ^ (v[2] << 16) ^ (v[3] >> 16) ^ (v[4] << 16) ^
    (v[5] >> 16) ^ v[5] ^ (v[6] >> 16) ^ (v[7] << 16) ^ (v[7] >> 16) ^ 
    (v[7] & 0xffff);
  h[1] = (v[0] << 16) ^ (v[0] >> 16) ^ (v[0] & 0xffff0000) ^ (v[1] & 0xffff) ^ 
    v[2] ^ (v[2] >> 16) ^ (v[3] << 16) ^ (v[4] >> 16) ^ (v[5] << 16) ^ 
    (v[6] << 16) ^ v[6] ^ (v[7] & 0xffff0000) ^ (v[7] >> 16);
  h[2] = (v[0] & 0xffff) ^ (v[0] << 16) ^ (v[1] << 16) ^ (v[1] >> 16) ^ 
    (v[1] & 0xffff0000) ^ (v[2] << 16) ^ (v[3] >> 16) ^ v[3] ^ (v[4] << 16) ^
    (v[5] >> 16) ^ v[6] ^ (v[6] >> 16) ^ (v[7] & 0xffff) ^ (v[7] << 16) ^
    (v[7] >> 16);
  h[3] = (v[0] << 16) ^ (v[0] >> 16) ^ (v[0] & 0xffff0000) ^ 
    (v[1] & 0xffff0000) ^ (v[1] >> 16) ^ (v[2] << 16) ^ (v[2] >> 16) ^ v[2] ^ 
    (v[3] << 16) ^ (v[4] >> 16) ^ v[4] ^ (v[5] << 16) ^ (v[6] << 16) ^ 
    (v[7] & 0xffff) ^ (v[7] >> 16);
  h[4] = (v[0] >> 16) ^ (v[1] << 16) ^ v[1] ^ (v[2] >> 16) ^ v[2] ^ 
    (v[3] << 16) ^ (v[3] >> 16) ^ v[3] ^ (v[4] << 16) ^ (v[5] >> 16) ^ 
    v[5] ^ (v[6] << 16) ^ (v[6] >> 16) ^ (v[7] << 16);
  h[5] = (v[0] << 16) ^ (v[0] & 0xffff0000) ^ (v[1] << 16) ^ (v[1] >> 16) ^ 
    (v[1] & 0xffff0000) ^ (v[2] << 16) ^ v[2] ^ (v[3] >> 16) ^ v[3] ^ 
    (v[4] << 16) ^ (v[4] >> 16) ^ v[4] ^ (v[5] << 16) ^ (v[6] << 16) ^
    (v[6] >> 16) ^ v[6] ^ (v[7] << 16) ^ (v[7] >> 16) ^ (v[7] & 0xffff0000);
  h[6] = v[0] ^ v[2] ^ (v[2] >> 16) ^ v[3] ^ (v[3] << 16) ^ v[4] ^ 
    (v[4] >> 16) ^ (v[5] << 16) ^ (v[5] >> 16) ^ v[5] ^ (v[6] << 16) ^ 
    (v[6] >> 16) ^ v[6] ^ (v[7] << 16) ^ v[7];
  h[7] = v[0] ^ (v[0] >> 16) ^ (v[1] << 16) ^ (v[1] >> 16) ^ (v[2] << 16) ^
    (v[3] >> 16) ^ v[3] ^ (v[4] << 16) ^ v[4] ^ (v[5] >> 16) ^ v[5] ^
    (v[6] << 16) ^ (v[6] >> 16) ^ (v[7] << 16) ^ v[7];
}

/* Clear the state of the given context structure. */

void gosthash_reset(GostHashCtx *ctx)
{
  memset(ctx->sum, 0, 32);
  memset(ctx->hash, 0, 32);
  memset(ctx->len, 0, 32);
  memset(ctx->partial, 0, 32);
  ctx->partial_bytes = 0;  
}

/* Mix in a 32-byte chunk ("stage 3") */

void gosthash_bytes(GostHashCtx *ctx, const unsigned char *buf, size_t bits)
{
  int i, j;
  unsigned long a, b, c, m[8];

  /* convert bytes to a long words and compute the sum */

  j = 0;
  c = 0;
  for (i = 0; i < 8; i++)
    {
      a = ((unsigned long) buf[j]) | 
    (((unsigned long) buf[j + 1]) << 8) | 
    (((unsigned long) buf[j + 2]) << 16) | 
    (((unsigned long) buf[j + 3]) << 24);
      j += 4;
      m[i] = a;
      b = ctx->sum[i];
      c = a + c + ctx->sum[i];
      ctx->sum[i] = c;
      c = ((c < a) || (c < b)) ? 1 : 0;     
    }

  /* compress */

  gosthash_compress(ctx->hash, m);

  /* a 64-bit counter should be sufficient */

  ctx->len[0] += bits;
  if (ctx->len[0] < bits)
    ctx->len[1]++;  
}

/* Mix in len bytes of data for the given buffer. */

void gosthash_update(GostHashCtx *ctx, const unsigned char *buf, size_t len)
{
  size_t i, j;

  i = ctx->partial_bytes;
  j = 0;
  while (i < 32 && j < len)
    ctx->partial[i++] = buf[j++];

  if (i < 32)
    {
      ctx->partial_bytes = i;
      return;
    }  
  gosthash_bytes(ctx, ctx->partial, 256);

  while ((j + 32) < len)
    {
      gosthash_bytes(ctx, &buf[j], 256);
      j += 32;
    }

  i = 0;
  while (j < len)
    ctx->partial[i++] = buf[j++];
  ctx->partial_bytes = i;
}


/* Compute and save the 32-byte digest. */

void gosthash_final(GostHashCtx *ctx, unsigned char *digest)
{
  int i, j;
  unsigned long a;

  /* adjust and mix in the last chunk */

  if (ctx->partial_bytes > 0)
    {
      memset(&ctx->partial[ctx->partial_bytes], 0, 32 - ctx->partial_bytes);
      gosthash_bytes(ctx, ctx->partial, ctx->partial_bytes << 3);      
    }

  /* mix in the length and the sum */

  gosthash_compress(ctx->hash, ctx->len);  
  gosthash_compress(ctx->hash, ctx->sum);  

  /* convert the output to bytes */

  j = 0;
  for (i = 0; i < 8; i++)
    {
      a = ctx->hash[i];
      digest[j] = (unsigned char) a;
      digest[j + 1] = (unsigned char) (a >> 8);
      digest[j + 2] = (unsigned char) (a >> 16);
      digest[j + 3] = (unsigned char) (a >> 24);    
      j += 4;
    }  
}

但是,没有一个main()函数可以用来编译一个可执行文件。我想要一个main(int argc, char *argv[])类型的主文件,用它调用带有生成的可执行文件的文件,并对文件的内容进行散列处理。

我已经重复了一遍又一遍的代码,但是我被困在调用代码的函数上,我不知道如何继续。请给我一些关于如何填充我的主要功能来运行这段代码的想法吗?

编辑

我尝试了以下main()代码,但它似乎不起作用:

代码语言:javascript
复制
void main(int argc, char *argv[]){
    if (argc!=2) {
        fprintf(stderr, "Error: Provide name of one source file.\n");
        exit(EXIT_FAILURE);
    }

    char *clear_file = argv[1];
    const char *FILENAME_IN = clear_file;

    FILE *infile;
    infile = fopen(FILENAME_IN, "r");

    GostHashCtx *ctx = malloc(sizeof(GostHashCtx));
    unsigned char *digest, *buf;
    char c;

    if(infile == NULL){
        fprintf(stderr, "Error: Source file not found.\n");
        exit(EXIT_FAILURE);
    }

    gosthash_init();
    gosthash_reset(ctx); //printf("CTX.PB=%d\n\n",ctx->partial_bytes);

    int quit = 0;
    while (quit == 0) {
        int p = 0;
        buf = malloc(256);
        strcpy(buf, "");
        while(((c = fgetc(infile)) != EOF) && (p < 256)) {
            *(buf+p) = c;
            p++;
        }

        //*(buf+p) = '\0';
        if(c == EOF) quit = 1;

        gosthash_update(ctx, buf, 256);
        free(buf);
    }

    digest = malloc(256); 
    strcpy(digest, "");

    gosthash_final(ctx, digest);

    printf("%s\n", digest);

    free(ctx);
    free(digest);
}

为了验证输出,我使用一个在线工具快速地将得到的字符串digest转换为HEX,但是对于已知的GOST散列测试值,结果是不正确的。拜托,你知道为什么会这样吗?

EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2015-07-21 20:07:01

好的,首先您必须调用gosthash_init来填充查找表。然后分配您所需的GostHashCtx类型的上下文--在您的情况下可能只需要一个上下文。您可以预先重置它,以确保上下文中填充了零值。

现在,您可以调用gosthash_update一次或多次,以散列文件中的所有字节(当然,按顺序排列)。最后,调用gosthash_final来创建哈希。这些步骤执行实际的散列。

如果您想散列其他东西,首先调用gosthash_reset,然后再调用gosthash_updategosthash_final

票数 1
EN

Stack Overflow用户

发布于 2015-07-24 20:29:36

当您到达文件的末尾时,如果文件长度不是256的倍数,则不会填充缓冲区,但仍然调用大小为256的gosthash_update,这意味着它将散列在缓冲区其余部分中的任何随机垃圾中。尝试将其更改为gosthash_update(ctx, buf, p);

也没有必要调用malloc --只需使用本地vars。您可以通过使用open/read而不是fopen/fgetc来简化事情:

代码语言:javascript
复制
char buf[2048];  /* or any size you like */
int len;
int fd = open(FILENAME_IN, O_RDONLY);
GostHashCtxt ctx;
gosthash_init();
gosthash_reset(&ctx);
while ((len = read(fd, buf, sizeof(buf)) > 0)
    gosthash_update(&ctx, buf, len);
gosthash_final(&ctx, buf);
write(1, buf, 32);

注意,结果摘要不是以空结尾的字符串--它是32字节的二进制数据。所以你不能安全地用printf("%s",打印

票数 0
EN

Stack Overflow用户

发布于 2015-07-30 19:29:01

如果其他人有相同的问题,我将在这里发布我的main()函数的最后代码。再次感谢“克里斯多德”和“MaartenBodewes”对他们的帮助。

编辑:,我已经为任何改进做了CW。(当前的代码在Windows环境下运行良好,但是在某些环境(如 Linux )中,由于指令gosthash_final(ctx, digest); (我追溯到gosthash_final()函数中对gosthash_compress()的调用),会发生故障。)

代码语言:javascript
复制
/* I used this function to get the hash result in HEX format */
void hexify(unsigned char *in, char *out) {
    char hex[64], tmp[3];
    int i; 
    hex[0]='\0';
    for(i=0; i<32; i++ )
    {
        sprintf(tmp, "%02X", in[i]);
        strcat(hex, tmp); 
    }
    strcpy(out, hex);
}

int main(int argc, char *argv[]){
    if (argc!=2) {
        fprintf(stderr, "Error: Provide name of one source file.\n");
        exit(EXIT_FAILURE);
    }

    char *clear_file = argv[1];
    const char *FILENAME_IN = clear_file;

    FILE *infile;
    infile = fopen(FILENAME_IN, "r");

    GostHashCtx *ctx = malloc(sizeof(GostHashCtx));
    unsigned char digest[32], buf[16];

    char hex[64];
    hex[0]='\0';

    if(infile == NULL){
        fprintf(stderr, "Error: Source file not found.\n");
        exit(EXIT_FAILURE);
    }

    gosthash_init();
    gosthash_reset(ctx); 

    size_t nread;
    while ((nread = fread(buf, 1, sizeof(buf), infile)) > 0)
        gosthash_update(ctx, buf, nread);
    fclose(infile);

    digest[0]='\0';
    gosthash_final(ctx, digest);

    hexify(digest, hex); 

    printf("HASH= %s\n", hex);

    free(ctx);
    return 0;
}
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原文链接:

https://stackoverflow.com/questions/31550616

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