如何快速使用块/闭锁

Question

在我的一个应用程序中，我使用块来调用webservice并获得响应。现在我想写这个应用程序的迅速，但我遇到麻烦，使用块/关闭在swift。以下是我想快速迁移的目标C代码：

调用通信器的类方法

[[Communicator sharedInstance]callWebService:WS_LOGIN withMethod:POST_METHOD andParams:params showLoader:YES completionBlockSuccess:^(id obj) {
   //Do play with data
}completionBlockFailiure:^(id obj) {
   //Show alert with error
}];

在通信器类

-(void)callWebService:(NSString *)serviceName withMethod:(NSString *)methodName andParams:(NSDictionary *)params showLoader:(BOOL)showLoader completionBlockSuccess:(void (^)(id))aBlock completionBlockFailiure:(void (^)(id))aFailBlock
{
   if (showLoader) {
   // show loader
   }
   [self performRequestWithServiceName:serviceName method:methodName andParams:params successblock:aBlock failureblock:aFailBlock];
}

- (void)performRequestWithServiceName:(NSString *)serviceName method:(NSString*)methodName andParams:(NSDictionary*)params
                 successblock:(void (^)(id obj))successBlock
                 failureblock:(void (^)(id obj))failBlock {
   if(callSuceess){
      successBlock(@"Success");
   }else{
      successBlock(nil);
   }
}

Answer 1

为了斯威夫特。对id objc类型使用AnyObject。

func callWebservice (serviceName: String, withMethod method: String, andParams params: NSDictionary, showLoader loader: Bool, completionBlockSuccess aBlock: ((AnyObject) -> Void), andFailureBlock failBlock: ((AnyObject) -> Void)) {
    if loader {
        // Show loader
    }

    performRequestWithServiceName(serviceName, method: method, andParams: params, success: aBlock, failure: failBlock)
}

func performRequestWithServiceName(serviceName: String, method methodName: String, andParams params: NSDictionary, success successBlock: ((AnyObject) -> Void), failure failureBlock: ((AnyObject) -> Void)) {
    if callSuceess {
        successBlock("Success")
    }else {
        successBlock(nil)
    }
}

UPDATE:想要调用web service的一个例子。见下面的代码

callWebservice("your-service-name", withMethod: "your-method", andParams: ["your-dic-key": "your dict value"], showLoader: true/*or false*/, completionBlockSuccess: { (success) -> Void in
    // your successful handle
}) { (failure) -> Void in
    // your failure handle
}

Answer 2

您的代码可能如下所示：

func callWebService(serviceName: String, method: String, params: [String : AnyObject], showLoader: Bool, success: (responseObject: AnyObject) -> Void, failure: (responseObject: AnyObject) -> Void) {
    if showLoader {
        // show loader
    }

    performRequest(serviceName, method: method, params: params, success: success, failure: failure)
}

func performRequest(serviceName: String, method: String, params: [String : AnyObject], success: (responseObject: AnyObject) -> Void, failure: (responseObject: AnyObject) -> Void) {

}

我用[String : AnyObject]代替了[String : AnyObject]。如果您可以用更具体的类型替换AnyObject的任何用途，您的代码就会更干净和更稳定。

Answer 3

对于Swift 闭包，我们必须使用( ) -> ( )

例如：

func yourFunction(success: (response: AnyObject!) -> Void, failure: (error: NSError?) -> Void) {

}

你可以称之为：

yourFunction({(response) -> Void in
    // Success
}) { (error) -> Void in
    // Handle Errors
}

希望它能帮助您根据需求创建闭包。