如何从php中的序列化数据中获取"file_url“？

Question

我希望从这里获得数据file_url：

a:1:{s:5:"bIrq7";a:6:{s:14:"user_file_name";s:15:"Recruitment.pdf";s:9:"file_name";s:15:"recruitment.pdf";s:9:"file_path";s:76:"/home3/fashion/public_html/thesafetyjobs.com/wp-content/uploads/ninja-forms/";s:8:"file_url";s:71:"http://thesafetyjobs.com/wp-content/uploads/ninja-forms/recruitment.pdf";s:8:"complete";s:1:"1";s:9:"upload_id";s:2:"28";}}`

我该怎么做？

Answer 1

尝试maybe_unserialize()函数--返回一个数组--您可以尝试以下代码

$data = 'a:1:{s:5:"bIrq7";a:6:{s:14:"user_file_name";s:15:"Recruitment.pdf";s:9:"file_name";s:15:"recruitment.pdf";s:9:"file_path";s:76:"/home3/fashion/public_html/thesafetyjobs.com/wp-content/uploads/ninja-forms/";s:8:"file_url";s:71:"http://thesafetyjobs.com/wp-content/uploads/ninja-forms/recruitment.pdf";s:8:"complete";s:1:"1";s:9:"upload_id";s:2:"28";}}';
$un_serialize = maybe_unserialize($data);
echo $un_serialize['bIrq7']['file_url'];