TypeError：“函数”对象不可迭代

Question

直到最近，这段代码才起作用。我添加了一个函数，提示用户输入一个文件名和扩展名，但是这不起作用，所以我求助于这个版本。现在，当我尝试运行它时，我得到了这个：

Traceback (most recent call last):
  File "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Parser/Single_File_Multistep_Counter.py", line 53, in <module>
main()
  File "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Parser/Single_File_Multistep_Counter.py", line 51, in main
writer(final_counts(intermediate_count))
  File "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Parser/Single_File_Multistep_Counter.py", line 31, in final_counts
for file_path in intermediate_file_list:
TypeError: 'function' object is not iterable

我还不完全确定错误意味着什么，在研究之后，我只能找到python object not iterable error in function和python3 TypeError: 'function' object is not iterable，它们不能解决我的问题。

下面是给我错误的代码：

def final_counts(intermediate_file_list):
    date_list = {}
    for file_path in intermediate_file_list:
        with open(file_path, "r") as f:
            for line in f:
                tockens = line.split(",")
                if tockens[0] in date_list:
                    date_list[tockens[0]] = date_list[tockens[0]] + tockens[1]
                else:
                    date_list[tockens[0]] = tockens[1]
    return date_list

如果需要的话，我将在以后的编辑中发布完整的代码。任何详细的答案解释我需要改变什么将是非常有帮助的，我想学习语言和我做错了什么，所以(希望)以后我不会犯同样的错误。

编辑：这里是我的全部代码

import os, glob, csv

location = "C:/Code/Samples/Dates/2015-06-07/Large-Scale Data Parsing/Data Files"
columnname = "smcn"
timecolumn = ""
filetype = ".processed"

def intermediate_count(location, filetype):
    intermediate_file_list = []
    for file_path in list(glob.glob(os.path.join(location, "*" + filetype))):
        date_list = {}
        print file_path
        with open(file_path, 'r') as f:
            for line in f:
                tockens = line.split(",")
                key = tockens[9] + "/" + tockens[15][:-4] #replace col_positon to 9 if necessary
                if key in date_list:
                    date_list[key] = date_list[key] + 1
                else:
                    date_list[key] = 1
        with open(file_path + ".count", "w") as csv:
            for item in date_list:
                csv.write(item + "," + str(date_list[item]) + "\n")
        intermediate_file_list.append(file_path + ".count")
    return intermediate_file_list

def final_counts(intermediate_file_list):
    date_list = {}
    for file_path in intermediate_file_list:
        with open(file_path, "r") as f:
            for line in f:
                tockens = line.split(",")
                if tockens[0] in date_list:
                    date_list[tockens[0]] = date_list[tockens[0]] + tockens[1]
                else:
                    date_list[tockens[0]] = tockens[1]
    return date_list

def writer(date_list):
    directory = location + "/" + "Total"
    if not os.path.exists(directory):
        os.makedirs(directory)
    with open(directory + "/" + "Total.processed", "w") as f: # Lots of commas!
        writer = csv.writer(f, delimiter=',', quotechar='|', quoting=csv.QUOTE_MINIMAL)
        for key, value in date_list.items():
            writer.writerow(str([key]) + str(value))

def main():
    writer(final_counts(intermediate_count))

main()

Answer 1

在黑暗中开枪：

intermediate_count是您创建的一个助手函数，它返回一个可迭代的。

解决方案(如果我的猜测是正确的)，您需要调用函数()，否则您正在传递函数对象本身，这是错误告诉您的。

writer(final_counts(intermediate_count(location, filetype)))
                                      ^

Answer 2

将main函数更改为如下所示：

def main():
    writer(final_counts(intermediate_count(location, filetype))

或者，您也可以这样写：

def main():
    writer(final_counts(intermediate_count())

然后改变这个：

def intermediate_count(location, filetype):

取而代之的是：

def intermediate_count():