makefile -命令在第一个目标之前开始

Question

我在启动makefile时收到了这条消息，最可能的错误是什么？它是制表符-分隔在每一行的开头。

makefile_first30samples_rfam:63: *** commands commence before first target.  Stop.

robinm@havpryd:~/Oluf/Project_GCF-2014-313$ head makefile_first30samples_rfam
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_007_GAGTGG.fastq > Cut_merged_007_GAGTGG.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_026_ATGTCA.fastq > Cut_merged_026_ATGTCA.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_030_GTGGCC.fastq > Cut_merged_030_GTGGCC.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_040_CACCGG.fastq > Cut_merged_040_CACCGG.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_086_AGTTCC.fastq > Cut_merged_086_AGTTCC.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_087_CCGTCC.fastq > Cut_merged_087_CCGTCC.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_125_CTTGTA.fastq > Cut_merged_125_CTTGTA.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_197_GCCAAT.fastq > Cut_merged_197_GCCAAT.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_208_CGTACG.fastq > Cut_merged_208_CGTACG.fastq
    #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_226_CAACTA.fastq > Cut_merged_226_CAACTA.fastq
robinm@havpryd:~/Oluf/Project_GCF-2014-313$ 

Answer 1

Makefile规则必须具有以下形式

target: ...
        command
        command

看来你的没找到目标线。

试着做些像

foo:
        #cutadapt -a TGGAATTCTCGGGTGCCAAGGAACTCCAGTCACATCACGATCTCGTATGCCGTCTTCTGCTTG merged_007_GAGTGG.fastq > Cut_merged_007_GAGTGG.fastq
        ...

(foo之前没有空格:每个命令之前有一个制表符)