Swift2 - HKSampleQuery

Question

let hkSampleType:HKSampleType = HKSampleType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKSampleQuery(sampleType: hkSampleType, predicate: predicate, limit: 80, sortDescriptors: nil, resultsHandler: { (query:HKSampleQuery, results:[HKSample]!, error:NSError!) -> Void in
    //code
})

就是这样，但我收到了一个错误：Cannot find an initializer for type 'HKSampleQuery' that accepts an argument list of type '(sampleType: HKSampleType, predicate: NSPredicate, limit: Int, sortDescriptors: nil, resultsHandler: (HKSampleQuery, [HKSample]!, NSError!) -> Void)'

怎样才是正确的语法？

Answer 1

我不是Swift或HealthKit方面的专家，但这是Xcode 7编译的：

let hkSampleType:HKSampleType = HKSampleType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKSampleQuery(sampleType: hkSampleType, predicate: nil, limit: 80, sortDescriptors: nil, resultsHandler: { (query:HKSampleQuery, results:[HKSample]?, error:NSError?) -> Void in
    //code
})

在闭包中，results和error是iOS 9中的选项，您将它们声明为未包装。

有一件事我不确定，那就是你能不能用HKSampleQuery来实现HKCorrelation。以下是HKCorrelationQuery的正确声明，以防您需要它：

let corralationType = HKCorrelationType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKCorrelationQuery(type: corralationType, predicate: nil, samplePredicates: nil) { (query: HKCorrelationQuery, results: [HKCorrelation]?, error: NSError?) -> Void in

}