我有一个读取的fastq文件,比如"reads.fastq“。我想将sequnces与保存为fasta文件ref.faa的字符串对齐。为此,我将使用以下代码
reads_array = []
for x in Bio.SeqIO.parse("reads.fastq","fastq"):
reads_array.append(x)
for x in Bio.SeqIO.parse("ref.faa","fasta"):
refseq = x
result = open("alignments_G10_final","w")
aligned_reads = []
for x in reads_array:
alignments =pairwise2.align.globalms(str(refseq.seq).upper(),str(x.seq),2,-1,-5,-0.05)
for a in alignments:
result.write(format_alignment(*a))
aligned_reads.append(x)但我只想报告每一次阅读的最佳排列。如何从a2的分数中选择这种对齐方式。我想选择a2值最高的对齐方式。
发布于 2015-06-18 11:01:54
您可以根据a2对对齐进行排序
for x in reads_array:
alignments = pairwise2.align.globalms(
str(refseq.seq).upper(), str(x.seq), 2, -1, -5, -0.05)
sorted_alignments = sorted(alignments, key=operator.itemgetter(2))
result.write(format_alignment(*sorted_alignments[0]))
aligned_reads.append(x)发布于 2019-04-02 00:01:50
我知道这是一个老问题,但对于那些仍在寻找正确答案的人,请在您的对齐方法中添加one_alignment_only=True参数:
alignments =pairwise2.align.globalms(str(refseq.seq).upper(),
str(x.seq),
2,-1,-5,-0.05,
one_alignment_only=True)为了找到它,我不得不在文档中做一些调查,但这给出了最佳的分数。
https://stackoverflow.com/questions/30905134
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