C，从文件输入到2d数组

Question

有谁能向我解释如何使C程序根据以下情况从文件中读取输入：

12
2-4,7,9;
1,4,11-12;
1,4,10,12;
1,4-8,10-12;
1,8;
1,3-6,8,10-12;
1,3,5-6,8,11;
1,8,10-12;
1-8;
;
2;
2-4,7-10,12;

第一个数字(在第一行)描述网格的大小，在本例中是12x12网格。下面的行描述网格中每一行占用了多少个单元格。例如，在第一行中，从2到4、7和9的单元格被占用；在第二行，单元格1、4和11到12被占用等等。

现在我有这个代码，但它不能解决我的问题.

#include <stdio.h>
#include <stdlib.h>

void main()
{   
    char content[3000];

    int value;
    FILE *ptr_file = fopen("data.txt", "r");
    if(!ptr_file)
        return 1;
    int j;

    while(fgets(content, 3000, ptr_file)!=NULL){
        printf("%s", content);
        value = atoi(content);   

        for(j=0; j<3000; j++){
            value = content[j];
            printf("%i", value);
        }
    }
    return 0;
}

控制台只抛出一堆随机数..。

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>

enum { EOD = -1, EOL = -2, ERR = -3, OFF = 0, ON = 1 };//End Of Data, End Of Line

int getValue(FILE *fp){
    static int on_yield = OFF, prev, end;

    if(on_yield == ON && prev < end){
        return ++prev;
    }
    on_yield = OFF;

    int n, ch = fgetc(fp);

    if(ch == EOF)
        return EOD;
    else if(ch == ';')
        return EOL;
    else if(ch == ',' || ch == '\n')
        return getValue(fp);//or change to using loop
    else if(isdigit(ch)){
        ungetc(ch, fp);
        fscanf(fp, "%d", &n);
        return prev=n;
    } else if(ch == '-'){
        on_yield = ON;
        fscanf(fp, "%d", &n);
        end = n;
        return getValue(fp);
    }
    fprintf(stderr, "(%c) invalid format in file\n", ch);
    return ERR;
}

int main(void){
    FILE *ptr_file = fopen("data.txt", "r");
    if(!ptr_file){
        perror("fopen");
        return 1;
    }

    int size;
    fscanf(ptr_file, "%d", &size);//check omitted
    char (*cell)[size] = malloc(size * sizeof(*cell));
    memset(&cell[0][0], ' ', size*size);

    int r = 0, c, value;
    while((value=getValue(ptr_file))!=EOD){
        if(value == EOL){
            ++r;
            continue;
        }
        if(value > 0)
            cell[r][value-1] = '*';
    }
    fclose(ptr_file);

    for(r = 0; r < size; ++r){
        for(c = 0; c < size; ++c){
            putchar(cell[r][c]);
        }
        putchar('\n');
    }
    free(cell);

    return 0;
}

Answer 2

伪码：

Open your file
Read the first line
    Extract the value N
    Allocate your grid
Loop N times
    Read a line
    If not an empty line, ie. semi-colon only
       Split into tokens by comma
       Check for a range or a single digit
       Extract numbers
       Set cells accordingly

Answer 3

“随机”数字是文件中的字节值，您忘了在行尾停止。Dave的解决方案不太适合c。在读了一行之后：

while not semicolon
    strtoul a number
    if no number
        exit error
    if next char is hyphen
        shift to next char
        strtoul end of range
        if no number
            exit error
        set cells
    else
        set cell
    if next char is not semicolon
        shift to next char

你不应该用阿托伊做任何事。使用sscanf或strto…。