Android -总是active active语句

Question

  public void myClick1(View v){
    EditText txtUser = (EditText) findViewById(R.id.strUser);
    EditText txtPwd = (EditText)findViewById(R.id.strPwd);

  if (txtUser.equals("admin")){
        Toast.makeText(getApplicationContext(),"Authentication Pass", Toast.LENGTH_LONG).show();
    }else{
        Toast.makeText(getApplicationContext(),"Not valid User ID/Password: " + txtUser.getText(), Toast.LENGTH_LONG).show();
}

无论我在文本框中输入了什么，它都会激活else语句。为什么？

Answer 1

您必须获得TextView的文本，如下所示：

    EditText txtUser = (EditText) findViewById(R.id.strUser);
    EditText txtPwd = (EditText) findViewById(R.id.strPwd);

    if ("admin".equals(txtUser.getText().toString())) {
        Toast.makeText(getApplicationContext(), "Authentication Pass", Toast.LENGTH_LONG).show();
    } else {
        Toast.makeText(getApplicationContext(),"Not valid User ID/Password: " + txtUser.getText(), Toast.LENGTH_LONG).show();
    }

Answer 2

在进行如下比较时，应该使用txtUser.getEditableText().toString()：

if ("admin".equals(txtUser.getEditableText().toString())){
    Toast.makeText(getApplicationContext(),"Authentication Pass", Toast.LENGTH_LONG).show();
}else{
    Toast.makeText(getApplicationContext(),"Not valid User ID/Password: " + txtUser.getText(), Toast.LENGTH_LONG).show();

Answer 3

我不熟悉android的自动取款机，但你试过：

txtUser.getText() == "admin“

谢谢您的评论(我使用的是C#方法)，固定代码：

txtUser.getText().equals("admin")