我的数据包括参与项目的不同个人的项目,以及项目实施的年份。
如何为每年创建一个nxn关系矩阵(n是个体的数量)来统计个人之间的协作数。
考虑以下再现所需结构的示例:
# Example dataframe
set.seed(1)
tp=cbind(paste(rep("project",10),1:10,sep=""),sample(2005:2010,10,replace=T))
tp=tp[sample(1:10,50,T),]
id=sample(paste(rep("id",10),1:10,sep=""),50,T)
df=as.data.frame(cbind(tp,id));rm(tp,id)
names(df)=c("project","year","id")
df=df[order(df$project,df$id),]
df[1:10,]
# project year id
# project1 2006 id1
# project1 2006 id3
# project1 2006 id5
# project1 2006 id5
# project4 2006 id3
# project4 2006 id4
# project5 2006 id3
# project5 2006 id4
# project6 2008 id2
# project6 2008 id3例如,2006年的关系矩阵如下所示
id1 id2 id3 id4 id5
id1 0 0 1 0 1
id2 0 0 0 0 0
id3 1 0 0 2 1
id4 0 0 2 0 0
id5 1 0 1 0 0
# link between 1 and 3, 1 and 5, 3 and 5 on project 1
# links between 3 and 4 on project 4 and project 5
# the matrix is symmetric
# the diagonal is O because an individual cannot collaborate with himself发布于 2015-06-04 14:54:33
您还可以将dplyr与tidyr一起用于以下内容:
library(dplyr)
library(tidyr)
df %>%
unique %>%
mutate(val = 1) %>%
spread(id, val) %>%
select(-project) %>%
group_by(year) %>%
do({
mat <- select(., -year) %>% as.matrix
mat[is.na(mat)] <- 0
cp <- crossprod(mat)
diag(cp) <- 0
cp %>% as.data.frame %>%
add_rownames(var = 'id')
}) %>%
ungrouphttps://stackoverflow.com/questions/30645066
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