我使用GridView和一个ListView控件来显示一些目录内容。我使用后面的代码动态加载ListView内容,创建GridViewColumns并将它们绑定到自定义catListItem类中的属性。
var view = new GridView();
var binding = new Binding("Name");
var resElement = _mResourceManager.GetElementByMdlID("vlu_usw_name_of");
view.Columns.Add(new GridViewColumn { Header = resElement.Name, DisplayMemberBinding = binding });
binding = new Binding("Number");
resElement = _mResourceManager.GetElementByMdlID("vlu_usw_arc_logical_nmbr");
view.Columns.Add(new GridViewColumn { Header = resElement.Name, DisplayMemberBinding = binding });一切都很好,但是现在我尝试使用CellTemplate属性添加带有图标的列。就像这样:
var view = new GridView();
var col = new GridViewColumn { Header = "" };
var template = new System.Windows.DataTemplate(typeof(Image));
col.CellTemplate = template;
view.Columns.Add(col);
var binding = new Binding("Name");
var resElement = _mResourceManager.GetElementByMdlID("vlu_usw_name_of");
view.Columns.Add(new GridViewColumn { Header = resElement.Name, DisplayMemberBinding = binding });
binding = new Binding("Number");
resElement = _mResourceManager.GetElementByMdlID("vlu_usw_arc_logical_nmbr");
view.Columns.Add(new GridViewColumn { Header = resElement.Name, DisplayMemberBinding = binding });我知道在使用DisplayMemberBinding、CellTemplate和CellTemplateSelector时有一个优先级。所以我的问题是:我如何创建(设置,.)CellTemplate的内容,并可能动态地将其绑定到自定义类的属性上?我不知道我错过了什么!我已经搜索过这个问题,但是我发现的都是使用DataTemplate的XAML解决方案。用后面的代码来做这件事很重要。提前感谢!
发布于 2015-06-03 13:46:01
实际上我找到了解决方案HERE
我不得不使用FrameworkElementFactory。下面是我要找的代码:
var column = new GridViewColumn { Header = "" };
var customTemplate = new System.Windows.DataTemplate();
var efImage = new FrameworkElementFactory(typeof(Image));
efImage.SetBinding(Image.SourceProperty, new Binding("Icon"));
customTemplate.VisualTree = efImage;
column.CellTemplate = customTemplate;
view.Columns.Add(column);https://stackoverflow.com/questions/30620058
复制相似问题