我有一套数据,其中包括病人在某一日期服用的药物疗程数。
subject<-c(111,111,111,222,222,333,333,333,333)
date<-as.Date(c("2010-12-12","2011-12-01","2009-8-7","2010-5-7","2011-3-7","2011-8-5","2013-8-27","2016-9-3","2011-8-5"))
medicationCourses<-c(1,0,NA,3,4,2,4,5,6)
data<-data.frame(subject,date,medicationCourses)
data
subject date medicationCourses
1 111 2010-12-12 1
2 111 2011-12-01 0
3 111 2009-08-07 NA
4 222 2010-05-07 3
5 222 2011-03-07 4
6 333 2011-08-05 2
7 333 2013-08-27 4
8 333 2016-09-03 5
9 333 2011-08-05 6我还有他们的入院日期。
hospitalSubject<-c(111,222,333)
admissionDate<-as.Date(c("2011-12-31","2013-12-31","2013-12-31"))
hospitalData<-data.frame(hospitalSubject,admissionDate)
hospitalData
hospitalSubject admissionDate
1 111 2011-12-31
2 222 2013-12-31
3 333 2013-12-31我想概述在收生日期或之前的药物治疗课程数目,并得出以下结果:
subject admissionDate totalMedicationCourses
111 2011-12-31 1
222 2013-12-31 7
333 2013-12-31 12我想知道有没有人能让我知道我怎么能在R中做到这一点?我是一个R的新手用户,所以任何的指导都将不胜感激!
发布于 2015-05-29 14:22:54
一种选择是由subject/hospitalSubject在两个数据集中使用subject/hospitalSubject将两个数据集中在一起,用date <= admissionDate表示行,并通过aggregate获得按'subject/admissionDate‘分组的'medicationCourses’的sum。
d1 <- subset(merge(data, hospitalData, by.x='subject',
by.y='hospitalSubject'), date <= admissionDate)
aggregate(medicationCourses~subject+admissionDate, d1, sum,
na.rm=TRUE, na.action=NULL)
# subject admissionDate medicationCourses
#1 111 2011-12-31 1
#2 222 2013-12-31 7
#3 333 2013-12-31 12或者我们可以使用data.table,将“data.frame”转换为“data.table”(setDT(data)),将键设置为“subject”(setkey(),并与hospitalData连接,过滤date <= admissionDate所在的行,并获得按“subject”和“admissionDate”分组的“医学课程”的sum。
library(data.table)
setkey(setDT(data), subject)[hospitalData][date <= admissionDate,
list(TotalMedicationCourses=sum(medicationCourses, na.rm=TRUE)),
list(subject, admissionDate)]
# subject admissionDate TotalMedicationCourses
#1: 111 2011-12-31 1
#2: 222 2013-12-31 7
#3: 333 2013-12-31 12或使用dplyr的类似方法
library(dplyr)
left_join(data, hospitalData, by=c('subject'='hospitalSubject')) %>%
filter(date <=admissionDate) %>%
group_by(subject, admissionDate) %>%
summarise(TotalMedicationCourses=sum(medicationCourses, na.rm=TRUE))https://stackoverflow.com/questions/30531955
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