这个问题与这个)有关。我正在将一个UIPickerView添加到一个没有在其接口中添加UIPickerViewDelegate或UIPickerViewDataSource协议的视图。但是,UIPickerView对象所需的所有方法都已正确实现,程序在以下委托下运行良好:
pv.delegate = self;
pv.dataSource = self; 由于没有在类接口中添加协议,Xcode相应地抛出这两个警告:
Assigning to 'id<UIPickerViewDelegate>' from incompatible type
Assigning to 'id<UIPickerViewDataSource>' from incompatible type这段代码似乎添加了所需的协议,并且一旦为选择器视图委托和数据源属性分配了新创建的delegateClass,警告就会停止。
UIPickerView *pv = [[UIPickerView alloc] initWithFrame:CGRectMake(x, y, width, height)];
Class<UIPickerViewDelegate, UIPickerViewDataSource> delegatedClass = (Class<UIPickerViewDelegate, UIPickerViewDataSource>)[self class];
pv.delegate = delegatedClass;
pv.dataSource = delegatedClass;但是,即使没有错误,程序也会崩溃。
执行或分配是否错误?
更新:错误的屏幕截图

发布于 2015-05-27 09:26:01
您正在尝试将类设置为委托。请设置实例以解决此问题。
UIPickerView *pv = [[UIPickerView alloc] initWithFrame:CGRectMake(x, y, width, height)];
pv.delegate = self;而不是
UIPickerView *pv = [[UIPickerView alloc] initWithFrame:CGRectMake(x, y, width, height)];
Class<UIPickerViewDelegate, UIPickerViewDataSource> delegatedClass = (Class<UIPickerViewDelegate, UIPickerViewDataSource>)[self class];
pv.delegate = delegatedClass;在定义自定义委托协议时,只使用
@property(nonatomic,assign)id delegate;而不是
@property(nonatomic,assign)id<YOUR_PROTOCOL> delegate;https://stackoverflow.com/questions/30478174
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