尝试为deform 2 (冒号1.0 )创建一个带有两个制表符(命令式样式)的表单。表单的思想是在手动添加网页和它的标题之间进行选择,或者选择一个提要URL:
@property
def webpage_form(self):
schema = colander.SchemaNode(colander.Mapping(unknown='preserve'),
name="webpage_schema")
schema_page = colander.SchemaNode(colander.Mapping(unknown='preserve'),
title=u"Webpage", missing={})
webpage_name = colander.SchemaNode(
colander.String(),
name='webpage_name',
default=u'Webpage',
missing=u'',
)
webpage_url = colander.SchemaNode(
colander.String(),
name='url',
default=u'-',
missing=u'',
)
schema_page.add(webpage_name)
schema_page.add(webpage_url)
schema_feed = colander.SchemaNode(colander.Mapping(unknown='preserve'),
title=u"Feed", missing={})
feed = colander.SchemaNode(
colander.String(),
name='feed_url',
default=u'-',
missing=u'',
)
schema_feed.add(feed)
schema.add(schema_page)
schema.add(schema_feed)
return deform.Form(schema, buttons=('submit',))在表单控制器(金字塔)中:
controls = request.POST.items()
...
appstruct = self.webpage_form.validate(controls)虽然控件似乎有数据,但是:
[('_charset_', u'UTF-8'),
('__formid__', u'deform'),
('__start__', u':mapping'),
('webpage_name', u'Webpage'),
('url', u'http://slashdot.org'),
('__end__', u':mapping'),
('__start__', u':mapping'),
('feed_url', u'-'),
('__end__', u':mapping'),
('submit', u'submit')]appstruct是空的:
{'': {}}尝试了标题,缺失,默认,未知的参数,没有结果。这个表格有什么问题?
另外,除了两个选项卡之外,还有两个相应的字段集,但这可能是另一个故事。
发布于 2015-05-27 09:52:51
解决了问题。name参数必须与colander.SchemaNode而不是title一起使用。然后,得到的appstruct如下所示:
{'feed': {'feed_url': u''},
'webpage': {'url': u'http://slashdot.org', 'webpage_name': u'Slashdot'}}这正是人们所期望的。
它有助于再次阅读医生们:
每个架构节点对象都有必需的类型、反序列化后调整数据的可选预报器、反序列化准备数据的可选验证器、可选的默认值、可选的缺失、可选的标题、可选的说明、和可选名称。
https://stackoverflow.com/questions/30460001
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