我正在编写一个用于创建jasper报告的oracle 10g查询。
这是一个问题-
SELECT essay_id,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (full_name, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS full_name
FROM (SELECT essay_id,
full_name,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY full_name)
AS curr,
ROW_NUMBER ()
OVER (PARTITION BY essay_id ORDER BY full_name)
- 1
AS prev
FROM (SELECT a.id AS essay_id,
CASE NVL (firstname, 'NULL FIRSTNAME')
WHEN 'NULL FIRSTNAME' THEN username
ELSE (firstname || ' ' || lastname)
END
AS full_name
FROM essay_table a
INNER JOIN essay_writer_join ej ON a.id = ej.essay_id
INNER JOIN writer_table u ON ej.user_id = u.id))
GROUP BY essay_id
CONNECT BY prev = PRIOR curr AND essay_id = PRIOR essay_id
START WITH curr = 1文章是独特的,但可以有多个作家(essay_writer_join),这个查询给我的文章与作家,是用逗号隔开。
问题是,我需要再添加一个名为" manager“的列,它将显示作者的经理。经理信息在WRITER_TABLE中,列名为"manager_name“。essay_table有作者的名字、姓氏和用户名。棘手之处在于,两个作家可以有两个不同的经理。例如,在论文“123”中,作者是'abc‘和'xyz’,这些作者的管理者分别是'lmo‘和'pqr’,那么记录应该以以下格式显示
essay id writer manager
123 abc, xyz lmo, pqr这在oracle 10g sql中是可能的吗?我试图寻找类似的情况,但没有找到任何相关的解决方案。
发布于 2015-05-22 11:32:10
您只需将manager_name包含在最内部的查询和中间的查询中,然后也可以重复该列的聚合机制。我已经更改了列和表别名,使之更加一致(我还简化了您的案例表达式):
SELECT essay_id,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (writer, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS writer,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (manager, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS manager
FROM (SELECT essay_id,
writer,
manager,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY writer)
AS curr,
ROW_NUMBER ()
OVER (PARTITION BY essay_id ORDER BY writer)
- 1
AS prev
FROM (SELECT et.id AS essay_id,
CASE WHEN wt.firstname IS NULL THEN wt.username
ELSE (wt.firstname || ' ' || wt.lastname)
END
AS writer,
wt.manager_name as manager
FROM essay_table et
INNER JOIN essay_writer_join ej ON et.id = ej.essay_id
INNER JOIN writer_table wt ON ej.user_id = wt.id))
GROUP BY essay_id
CONNECT BY prev = PRIOR curr AND essay_id = PRIOR essay_id
START WITH curr = 1;
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr 我能看到的唯一真正的问题是,如果一篇文章的两位作者都有相同的管理者,那么你会看到这个价值被重复了:
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr
456 abc,def lmo,lmo 这也许是你想要看到的。
演示。
如果您确实希望抑制重复的管理器,则可以将聚合分离为子查询。我发现,将这些内容放入常见的表表达式(a.k.a )中更容易阅读。(子查询重构):
WITH all_data AS (
SELECT et.id AS essay_id,
CASE WHEN wt.firstname IS NULL THEN wt.username
ELSE (wt.firstname || ' ' || wt.lastname)
END
AS writer,
wt.manager_name as manager
FROM essay_table et
JOIN essay_writer_join ej ON et.id = ej.essay_id
JOIN writer_table wt ON ej.user_id = wt.id
),
writers AS (
SELECT essay_id,
writer,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY writer) AS rn
FROM (
SELECT distinct essay_id, writer
FROM all_data
)
),
managers AS (
SELECT essay_id,
manager,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY manager) AS rn
FROM (
SELECT distinct essay_id, manager
FROM all_data
)
)
SELECT DISTINCT ad.essay_id,
(
SELECT LTRIM (MAX (SYS_CONNECT_BY_PATH (w.writer, ','))
KEEP (DENSE_RANK LAST ORDER BY w.rn), ',')
FROM writers w
WHERE w.essay_id = ad.essay_id
CONNECT BY w.rn = PRIOR w.rn + 1 AND w.essay_id = PRIOR w.essay_id
START WITH w.rn = 1
) AS writer,
(
SELECT LTRIM (MAX (SYS_CONNECT_BY_PATH (m.manager, ','))
KEEP (DENSE_RANK LAST ORDER BY m.rn), ',')
FROM managers m
WHERE m.essay_id = ad.essay_id
CONNECT BY m.rn = PRIOR m.rn + 1 AND m.essay_id = PRIOR m.essay_id
START WITH m.rn = 1
) AS manager
FROM all_data ad
ORDER BY ad.essay_id;重要的一点是,分配行号的每个子查询都使用自己的内联视图来获得不同的值。因此,对于获取以下内容的相同数据:
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr
456 abc,def lmo SQL Fiddle。
https://stackoverflow.com/questions/30384412
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