函数NameError

Question

我一直在处理一些代码，试图创建一个用于工作计划的函数。但是我被困住了，想知道是否有人能帮上忙？谢谢

class Work_plan(object):
    def __init__(self,hours_work,work_len, work_des):
        self.hours_work = hours_work
        self.work_len = work_len
        self.work_des = work_des

        work_load = []
        hours_worked = []
        if hours_worked > hours_work:
            print "Too much work!"
        else:
            work_load.append(work_des)
            hours_worked.append(work_len)
            print "The work has been added to your work planning!"

work_request = Work_plan(8, 2, "task1")
Work_plan
print work_load

它产生了一个错误: NameError: name 'work_load‘未定义

Answer 1

您在类的work_load中定义了变量__init__，因此不能在此范围之外访问它。

如果您想要访问work_load，请将它作为Work_plan类对象的属性，并通过执行object.work_plan访问它。

例如：

class Work_plan(object):
    def __init__(self,hours_work,work_len, work_des):
        self.hours_work = hours_work
        self.work_len = work_len
        self.work_des = work_des

        self.work_load = []
        self.hours_worked = []
        if hours_worked > hours_work:
            print "Too much work!"
        else:
            self.work_load.append(work_des)
            self.hours_worked.append(work_len)
            print "The work has been added to your work planning!"

work_request = Work_plan(8, 2, "task1")
Work_plan
print work_request.work_load