假设我有这样一个数组:
Array
(
[0] => Array
(
[0] => A
[1] => 20
)
[1] => Array
(
[0] => B
[1] => 10
)
[2] => Array
(
[0] => G
[1] => 5
)
[3] => Array
(
[0] => A
[1] => 15
)
)我想移除重复的值,只和一行数组:我想要的是:
Array
(
[0] => Array
(
[0] => A
[1] => 35 // <= sum : 20 + 15
)
[1] => Array
(
[0] => B
[1] => 10
)
[2] => Array
(
[0] => G
[1] => 5
)
)我以前读过this的问题。
更新
while($row = $stmt->fetch()){
$arr = array(
'GoodMainCode'=>persian_sql_to_php($row['GoodMainCode']), // <= like A in the example
'title'=> persian_sql_to_php($row['GoodName']),
'author'=>persian_sql_to_php($row['moalef']),
'publisher'=>persian_sql_to_php($row['Nasher']),
'translator'=>persian_sql_to_php($row['Motarjem']),
'price'=>persian_sql_to_php($row['SellPrice1']),
'isbn'=>persian_sql_to_php($row['ISBN']),
'amount'=>persian_sql_to_php($row['Amount']), // <= if GoodMainCode is same key, I must sum it.
'year_of_publish'=>persian_sql_to_php($row['SaleChap']),
'period_print'=>persian_sql_to_php($row['NobateChap'])
);
array_push($mjson,$arr);
}
//added
foreach($mjson as $v){
if(!isset($result[$v['GoodMainCode']]))
$result[$v['GoodMainCode']] = $v;
else
$result[$v['GoodMainCode']]['amount'] += $v['amount'];
}发布于 2015-05-16 09:33:36
这应该适用于你:
只需循环遍历数组,并检查$result数组中是否有来自$arr的当前内部数组的字母键。如果没有,则将其添加到$result数组中,并使用数字初始化第二个键。
如果这个字母已经有一个键,您可以简单地将这些数字相加在这个数组中。最后,我只需使用array_values()重新索引整个数组。
<?php
foreach($arr as $v) {
if(!isset($result[$v[0]]))
$result[$v[0]] = $v;
else
$result[$v[0]][1] += $v[1];
}
$result = array_values($result);
print_r($result);
?>产出:
Array
(
[0] => Array
(
[0] => A
[1] => 35
)
//...
[2] => Array
(
[0] => G
[1] => 5
)
)https://stackoverflow.com/questions/30273948
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