我是拉勒维尔的新手,有这样的迁徙:
public function up()
{
Schema::table('mytable', function(Blueprint $table)
{
$table->renameColumn('mycol', 'old_mycol');
$table->string('mycol', 100);
});
}当我运行它时,我会得到错误:
PDOException SQLSTATE42S21:列已经存在: 1060重复列名'mycol‘
最后,我把它分成了两个单独的迁移,这很好,但是我不明白为什么一次做它是一个问题。
发布于 2015-05-16 02:14:37
这是因为在执行迁移时,Laravel将隐式地在命令数组的开头放置任何添加新列或修改现有列的命令。以下代码直接取自Illuminate\Database\Schema\Blueprint类。
/**
* Get the raw SQL statements for the blueprint.
*
* @param \Illuminate\Database\Connection $connection
* @param \Illuminate\Database\Schema\Grammars\Grammar $grammar
* @return array
*/
public function toSql(Connection $connection, Grammar $grammar)
{
$this->addImpliedCommands();
$statements = array();
// Each type of command has a corresponding compiler function on the schema
// grammar which is used to build the necessary SQL statements to build
// the blueprint element, so we'll just call that compilers function.
foreach ($this->commands as $command)
{
$method = 'compile'.ucfirst($command->name);
if (method_exists($grammar, $method))
{
if ( ! is_null($sql = $grammar->$method($this, $command, $connection)))
{
$statements = array_merge($statements, (array) $sql);
}
}
}
return $statements;
}
/**
* Add the commands that are implied by the blueprint.
*
* @return void
*/
protected function addImpliedCommands()
{
if (count($this->getAddedColumns()) > 0 && ! $this->creating())
{
array_unshift($this->commands, $this->createCommand('add'));
}
if (count($this->getChangedColumns()) > 0 && ! $this->creating())
{
array_unshift($this->commands, $this->createCommand('change'));
}
$this->addFluentIndexes();
}正如您从上面的代码中看到的,在toSql方法中,有一个对addImpliedCommands的调用,其中几个命令可能被添加到对象的命令数组的开头。这将导致在重命名命令之前首先执行新mycol列的命令。
为了解决这个问题,您实际上不需要创建两个迁移。在相同的迁移中,您只需调用Schema::table()两次,如下所示:
Schema::table('mytable', function(Blueprint $table)
{
$table->renameColumn('mycol', 'old_mycol');
});
Schema::table('mytable', function(Blueprint $table)
{
$table->string('mycol', 100);
});https://stackoverflow.com/questions/30270558
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