把TableLayoutPanel丢到面板上？

Question

我正在使用winforms/c#为面板中的tablelayoutpanel尝试拖放，但是问题是tablelayout的拖放没有出现!！有什么解决办法吗?？

private void Registration_Load(object sender, EventArgs e)
{   
     panel2.AllowDrop = true;
     tableLayoutPanel1.AllowDrop = true;
     panel2.DragEnter += panel2_DragEnter;   
     panel2.DragDrop += panel2_DragDrop;
     tableLayoutPanel1.MouseDown += tableLayoutPanel1_MouseDown;
}   

private void panel2_DragEnter(object sender, DragEventArgs e)
{
    e.Effect = DragDropEffects.Move;
}

private void panel2_DragDrop(object sender, DragEventArgs e)
{
     ((TableLayoutPanel)e.Data.GetData(typeof(TableLayoutPanel))).Parent (Panel)sender;                
}
private void tableLayoutPanel1_MouseDown(object sender, MouseEventArgs e)
{
     tableLayoutPanel1.DoDragDrop(tableLayoutPanel1, DragDropEffects.Move);
}

Answer 1

代码不足，您至少需要设置已丢弃的TLP的Location属性，以确保其位于面板边界内和/或位于鼠标光标处。而Z-order很重要，将父属性设置在底部，这样面板中的其他控件就可以很容易地重叠，您需要BringToFront()。

试试这个：

    private void panel2_DragEnter(object sender, DragEventArgs e) {
        if (e.Data.GetDataPresent(typeof(TableLayoutPanel))) e.Effect = DragDropEffects.Move;
    }

    private void panel2_DragDrop(object sender, DragEventArgs e) {
        var tlp = (TableLayoutPanel)e.Data.GetData(typeof(TableLayoutPanel));
        tlp.Location = panel2.PointToClient(new Point(e.X, e.Y));
        tlp.Parent = panel2;
        tlp.BringToFront();
    }