基于Ruby & Regex的文本挖掘清理

Question

我有一个单词计数散列，如下所示：

words = {
  "love"   => 10,
  "hate"   => 12,
  "lovely" => 3,
  "loving" => 2,
  "loved"  => 1, 
  "peace"  => 14,
  "thanks" => 3,
  "wonderful" => 10,
  "grateful" => 10
  # there are more but you get the idea
}

我想确保“爱”、“爱”和“爱”都算作“爱”。因此，我把它们加在一起，作为“爱”的计数，去掉“爱”的其余部分。然而，同时，我不希望“可爱”被视为“爱”，所以我保留它的原样。

所以我最终会得到这样的东西。

words = [
  "love"   => 13,
  "hate"   => 12,
  "lovely" => 3,
  "peace"  => 14,
  "thanks" => 3,
  "wonderful" => 10,
  "grateful" => 10
  # there are more but you get the idea
]

我有一些代码可以工作，但我认为最后一行的逻辑是错误的。我想知道你是否能帮我解决这个问题，或者建议一个更好的方法。

words.select { |k| /\Alov[a-z]*/.match(k) }
words["love"] = purgedWordCount.select { |k| /\Alov[a-z]*/.match(k) }.map(&:last).reduce(:+) - 1 # that 1 is for the 1 for "lovely"; I tried not to hard code it by using words["lovely"], but it messed things up completely, so I had to do this. 
words.delete_if { |k| /\Alov[a-z]*/.match(k) && k != "love" && k != "lovely" }

谢谢!

Answer 1

words = {
  "love"   => 10,
  "hate"   => 12,
  "lovely" => 3,
  "loving" => 2,
  "loved"  => 1,
  "peace"  => 14,
  "thanks" => 3,
  "wonderful" => 10,
  "grateful" => 10
  # there are more but you get the idea
}

aggregated_words = words.inject({}) do |memo, (word, count)|
  key = word =~ /\Alov.+/ && word != "lovely" ? "love" : word
  memo[key] = memo[key].to_i + count
  memo
end

> {"love"=>13, "hate"=>12, "lovely"=>3, "peace"=>14, "thanks"=>3, "wonderful"=>10, "grateful"=>10}

Answer 2

我建议如下：

r = /
    lov     # match 'lov'
    (?!ely) # negative lookahead to not match 'ely'
    [a-z]+  # match one or more letters
            # /x is for 'extended', /i makes it case-independent
    /xi

words.each_with_object(Hash.new(0)) { |(k,v),h| (k=~r) ? h["love"]+=v : h[k]=v }
  #=> {"love"=>13, "hate"=>12, "lovely"=>3, "peace"=>14, "thanks"=>3,
  #    "wonderful"=>10, "grateful"=>10} 

Answer 3

下面是功能无损版本

words = {
  "love"   => 10,
  "hate"   => 12,
  "lovely" => 3,
  "loving" => 2,
  "loved"  => 1, 
  "peace"  => 14,
  "thanks" => 3,
  "wonderful" => 10,
  "grateful" => 10
}

to_love_or_not_to_love = words.partition {|w| w.first =~ /^lov/ && w.first != "lovely"}

{"love" => to_love_or_not_to_love.first.map(&:last).sum}.merge(to_love_or_not_to_love.last.reduce({}) {|m, e| m[e.first] = e.last; m})

=> {“爱”=>13，“恨”=>12，“可爱的=>3”，“和平”=>14，“谢谢”=>3，“美妙的”=>10，“感激的”=>10