从文本中提取工作经验的Regex

Question

我正在尝试创建一个通用的regex，从文本中提取工作经验。

请考虑以下示例及其预期结果。

1)String string1= "My work experience is 2 years"

Output = "2 years"

2) String string2 = "My work experience is 6 months"

Output = "6 months"

我使用regex作为/[0-9] years/，但它似乎不起作用。

如果有人认识一个将军，请分享。

Answer 1

您可以使用替换：

String str = "My work experience is 2 years\nMy work experience is 6 months";
String rx = "\\d+\\s+(?:months?|years?)";
Pattern ptrn = Pattern.compile(rx);
Matcher m = ptrn.matcher(str);
while (m.find()) {
     System.out.println(m.group(0));
}

请参阅IDEONE演示

输出：

2 years
6 months

或者，您也可以获得类似于以下3 years 6 months的字符串：

String str = "My work experience is 2 years\nMy work experience is 3 years 6 months and his experience is 4 years and 5 months";
String rx = "\\d+\\s+years?\\s+(?:and\\s*)?\\d+\\s+months?|\\d+\\s+(?:months?|years?)";
Pattern ptrn = Pattern.compile(rx);
Matcher m = ptrn.matcher(str);
while (m.find()) {
    System.out.println(m.group(0));
}

另一个演示输出

2 years
3 years 6 months
4 years and 5 months

Answer 2

我建议使用这个正则表达式：

String regex = "\\d+.*$"