浏览一个表并在javascript中的两个表上共享它

Question

我有一个表，它遵循一个定义的序列: col，name，value1，value2，value 3，col，name value1，value2，value3 ..col，name，value1，value2，value 3

代码：

 var data =["DN","Atac","1","2","3","PDA","Atac","5","6","7","EPDA","Atac","8","9","11","DN Potentielle","Atac","14","4","8"] ;

我尝试拆分数据表col、name、value: Code结果：

var column = ["DN","PDA","EPDA","DN Potentielle"];
var name ="Atac";
var values =[ "1","2","3","5","6","7","8","9","11","14","4","8"];

如果没有大量的代码，最简单的方法是如何做到的呢？

Answer 1

如果您确信您的数据是一致的，并且可以依赖您编写的结构，那么最简单的是：

var column = [];
var name = [];
var values = [];
for (var i = 0; i < data.length; i = i+5) {
    column.push(data[i]);
    name.push(data[i+1]);
    values.push(data[i+2]);
    values.push(data[i+3]);
    values.push(data[i+4]);
};

name = name.filter(function(value, index, self) { 
    return self.indexOf(value) === index;
});

console.log(column); //["DN","PDA","EPDA","DN Potentielle"]
console.log(name); //["Atac"]
console.log(values); //["1", "2", "3", "5", "6", "7", "8", "9", "11", "14", "4", "8"]

小提琴

Answer 2

设置一个对象来保存以下值：

var obj = { column: [], name: null, values: [] };

然后以5组形式循环数组，将各种元素添加到对象中：

for (var i = 0, l = data.length; i < l; i+=5) {
  obj.column.push(data[i]);
  obj.name = data[i + 1];

  // push.apply is a neat way of concatenation that doesn't
  // require the creation of a new variable
  obj.values.push.apply(obj.values, data.slice(i + 2, i + 5));
}

演示

Answer 3

我试图找出您想要的内容，最好的方法是检索数字值和字符串值，而不分割它。

var data =["DN","Atac","1","2","3","PDA","Atac","5","6","7","EPDA","Atac","8","9","11","DN Potentielle","Atac","14","4","8"] ;
var columns = [];
var values = [];
$.each(data, function(k, v) {
    var parsedValue = parseInt(data[k]);
    if ( ! isNaN(parsedValue) ) {
        values.push(parsedValue);
    } else {
        columns.push(v);
    }

});
console.log(columns);
console.log(values);

演示：http://jsfiddle.net/bzryqs84/1/